Answer:
(1)
And for this case we know the following condition "The length of the field is 7 yards less than quadruple the width" and we can write this :

And replacing into equation (1) we got:



Adding 14 in both sides we got:

And dividing 10 on both sides we got:

And then we can solve for X and we got:

Step-by-step explanation:
For this case we can set up the following notation:
X represent the lenght
Y represent the width
And since we have a rectangular playing filed the perimeter is given by:
(1)
And for this case we know the following condition "The length of the field is 7 yards less than quadruple the width" and we can write this :

And replacing into equation (1) we got:



Adding 14 in both sides we got:

And dividing 10 on both sides we got:

And then we can solve for X and we got:

If A=38x-x^2 then
dA/dx=38-2x
d2A/dx2=-2
Since the acceleration, d2A/dx2 is a constant negative, when velocity, dA/dx=0, it will be an absolute maximum for A(x)
dA/dx=0 only when 38=2x, x=19
A(19)=38(19)-19^2
A(19)=722-361
A(19)=361 ft^2
So the maximum possible area is 361 ft^2
(This will always be true as the maximum possible area enclosed by a given amount of material will always be a perfect square...)
Answer:
LCM of 3 and 4 is 12
Step-by-step explanation:
This is your answer
Is it is multiplication it is 116 in division 29