Question

5

Answer 1

The corresponding frequency  is $6.25 \times 10^{14} \mathrm{Hertz}$

Step-by-step explanation:

Given:

The brightest light is emitted =0.48 μm

To find:

Frequency= ?

Solution:

We know ,

$1 \mu m=10^{-6} \text { meters }$

Hence,

$0.48 \mu m=0.48 \times 10^{-6} \mathrm{meters}$

Now,

$\text {frequency }=\frac{\text {speed of lightc}}{\text {wavelength}}$

Substituting the known values

$\text { frequency }=\frac{\left(3.00 \times 10^{8} \text { meters per second }\right)}{\left(0.48 \times 10^{-6} \mathrm{meters}\right)}$

$\text {frequency }=6.25 \times 10^{14} \mathrm{Hertz}$

Thus the frequency is $6.25 \times 10^{14} \mathrm{Hertz}$