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Levart [38]
3 years ago
8

A school has two varsity basketball teams. One is the girls' team, and the other is the boys' team. On any given Saturday in Dec

ember, the probability that the girls' team will have a game is 0.8, and the probability that the boys' team will have a game is 0.7. The probability that both teams have games is 0.65.
On any given Saturday in December, what is the probability that either the girls' team or the boys' team has a game?
Answer choices:
0.65
0.7
0.8
0.85
Mathematics
1 answer:
belka [17]3 years ago
5 0

The probability that either the girls' or boys' team gets a game is 0.85            

Step-by-step explanation:

Step 1:

Let P(G) represent the probability of girls team getting a game and P(B) represent the probability of the boys team getting a game.

P(B ∪ G) represents the probability of either girls and boys team getting a game.

P(B ∩ G) represents the probability of both girls and boys team getting a game.

Step 2:

It is given that P(G) = 0.8, P(B) = 0.7 and P(B ∩ G) = 0.65

We need to find the probability of either girls or boys team getting a game which is represented by P(B ∪ G)

Step 3:

P(B ∪ G) = P(B) + P(G) - P(B ∩ G)

= 0.8 + 0.7 - 0.65 = 0.85

Step 4:

Answer:

The probability that either the girls' or boys' team gets a game is 0.85

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Mr. Sawyer drove his car from his home to New York at the rate of 45 mph and returned over the same road at the rate of 40 mph.
AveGali [126]

Answer: Time taken by him in going = 8 hours

Time taken by him in returning =  9 hours

Step-by-step explanation:

Let the total distance from home to New York is x miles,

\text{ Since, Time} = \frac{\text{Distance}}{\text{Speed}}

Also, he drove his car from his home to New York at the rate of 45 mph,

⇒ \text{ Time taken by him in going } = \frac{x}{45}\text{ hours}

And, returned over the same road at the rate of 40 mph.

⇒  \text{ Time taken by him in returning } = \frac{x}{40}\text{ hours}

According to the question,

Time taken by him in returning - Time taken by him in going = 30 minutes = 1/2 hours,    ( 1 hours = 60 minutes )

⇒ \frac{x}{40}-\frac{x}{45}=\frac{1}{2}

⇒ \frac{9x}{360}-\frac{8x}{360}=\frac{1}{2}

⇒ \frac{x}{360} = \farc{1}{2}

⇒ 2x=720

⇒ x=360\text{ miles}

Hence, the total distance from home to New York = x miles = 360 miles

⇒ \text{ Time taken by him in going } = \frac{x}{45}\text{ hours}

=\frac{360}{45}=8\text{ hours}

⇒  \text{ Time taken by him in returning } = \frac{x}{40}\text{ hours}

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3 0
3 years ago
Thank you guys fir the help
Lubov Fominskaja [6]
The correct answer to that would be b
4 0
3 years ago
What is the area of the shape below
Bad White [126]

Answer:

The area of the shape is A=886 \:cm^2.

Step-by-step explanation:

The shape in the graph is a composite figure is made up of several simple geometric figures such as triangles, and rectangles.

Area is the space inside of a two-dimensional shape. We can also think of area as the amount of space a shape covers.

To calculate the area of a composite shape you must divide the shape into rectangles, triangles or other shapes you can find the area of and then add the areas back together.

First  separate the composite shape into three simpler shapes, in this case two rectangles and  a triangle. Then find the area of each figure.

To find the area of a rectangle, we multiply the length of the rectangle by the width of the rectangle.

The area of the first rectangle is A=34\cdot 16=544\:cm^2

The area of the second rectangle is A=11\cdot19=209\: cm^2

The area of a triangle is given by the formula A=\frac{1}{2} bh where <em>b</em> is the base and <em>h</em> is the height of the triangle.

The area of the triangle is A=\frac{1}{2} \cdot 14\cdot19=133\:cm^2

Finally, add the areas of the simpler figures together to find the total area of the  composite figure.

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den301095 [7]

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Step-by-step explanation:

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Time taken to travel this distance = 40 seconds - 10 seconds = 30 seconds

Diver's rate of travel = 70 ft / 30 seconds = 2.33333ft/second.

Rounding off the answer to the nearest tenth, we have 2.3 ft/second

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garri49 [273]
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