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Pachacha [2.7K]
3 years ago
13

molly is 5 years younger than her sister. The sum of their ages is 37. Define a variable. write an equation and then molly's age

.
Mathematics
1 answer:
k0ka [10]3 years ago
5 0
I will take M as molly and S as her sister

M=x-5
S=x
M+S=37
X-5+x=37
2x-5=37
Now you add 5 on both sides so you get 2x=37+5
-5 on other becomes 0 because when you add +5 and -5 get cancels out
So I am left with 2x=37+5
2x=42
Than you divide 2 on both side to get x alone so you are left with
X=(42/2)
X=21

Molly’s age equation is x-5
Now you plug x into the equation so you get
21-5
And that’s equal to 16
So Molly’s age is 16 years
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x=-3 then y= 27

x= -2 then y= 9

x=2 then y: y=\frac{1}{9}

x=3 then y: y=\frac{1}{27}

The graph of the function decreases from left to right.

Option C is correct.

Step-by-step explanation:

We are given the function: y=(\frac{1}{3})^x

and we need to fill the table

if x = -3 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^-3

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^3 }\\y=\frac{1}{\frac{1}{27}}\\y=27

if x = -2 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^-2

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^2 }\\y=\frac{1}{\frac{1}{9}}\\y=9

if x = 2 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^2

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^2 }\\y=\frac{1}{9}

if x = 3 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^3

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^3 }\\y=\frac{1}{27}

So, x=-3 then y= 27

x= -2 then y= 9

x=2 then y: y=\frac{1}{9}

x=3 then y: y=\frac{1}{27}

Graph of the function is shown in figure attached.

The graph of the function decreases from left to right.

Option C is correct.

Keywords: Solving Equations

Learn more about Solving Equations at:

  • brainly.com/question/1563227
  • brainly.com/question/2403985
  • brainly.com/question/11229113

#learnwithBrainly

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4 years ago
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