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3 years ago

-13/10x - 3/2 (11/6x +1)

1 answer:

4 0

So first simplify 11/6x into 11x/6. Then -13/10x into -13x/10. So you should now have (-13x/10-11x/4)-3/2. Combine the like terms -13x/10 and -11x/4 to get -81x/20 and then with your left over -3/2= -81x/20-3/2

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You have just timed a person doing a hair cut for the first time. It took 50 minutes. What unit improvement factor learning curv

Sladkaya [172]

Answer: C. 70 percent

Step-by-step explanation:

Given, Time for the first unit = 50 minutes

Time for the second unit = 35 minutes

The unit improvement factor learning curve = (The time for the second unit) ÷ (time for the first unit) x 100.

So, The unit improvement factor learning curve = 35÷ 50 × 100 = 70 percent.

Hence, the correct option is "C. 70 percent".

3 0

3 years ago

Find the measure of 7

fredd [130]

Answer:

126 degree

Step-by-step explanation:

use alternate angles and linear pair

7 0

3 years ago

First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

3 years ago

Amaya wants to jog 8 Miles this week she has jog 2 1/2 miles on Monday and 3 2/5 miles on Wednesday how many miles does amaya st

olasank [31]

Answer:

2 1/10 miles.

Step-by-step explanation:

She has already jogged 2 1/2 + 3 2/5 miles. This is 2 5/10 + 3 4/10 or 5 9/10. 8 miles is also equal to 7 10/10 miles. So, to find the remaining amount of miles, we can do 7 10/10 - 5 9/10 = 2 1/10.

5 0

3 years ago

Out of 25 students, 15 students are girls. what is the ratio of boys and girls? a: 3:5 b: 2:5 c: 2:3

Vadim26 [7]

Answer:

Answer: C 2:3

Step-by-step explanation:

total students = 25

total girls = 15

total boys = 25-15 = 10

boys:girls = 10:15

divide by 5 to get 2:3

6 0

1 year ago