15 and 6.
15+ 6 = 21
15^2 + 6^2 = 261
Answer:
2
Step-by-step explanation:
(4+6)/(5)
10/5
=2
Answer:
Step-by-step explanation:
Integer factors of 117 include ...
... 117 = 1×117 = 3×39 ≈ 9×13
The last factor pair is two factors that differ by 4. We can take these to be the dimensions of the rectangle.
_____
If you want to write an equation for width (w), it might be ...
... w(w+4) = 117
... w² +4w -117 = 0
The factorization problem for this quadratic is the problem of finding two factors of 117 that differ by 4. That is what we have done, above.
If you want to solve this by completing the square, you can to this:
... w² +4w = 117
... w² +4w +4 = 121 . . . . . add 4 = (4/2)² to complete the square
... (w+2)² = 121
... w + 2 = ±√121 = ±11 . . . . take the square root
... w = -2 ± 11 . . . . . we're only interested in the positive solution
... w = 9, then w+4 = 13 and the dimensions are 9 cm by 13 cm.
Inequalities will have a <, >, <=, =>, = or will be worded as "Less than", "greater than", etc.
Equations must have mathematical functions and equal sign.
15=3x is an equation since 3x = 3*x
Finally, expressions are mathematical functions that have no equal signs.
Step-by-step explanation:
<em><u>AB+BC+CA</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>A</u></em><em><u>C</u></em><em><u> </u></em><em><u>+</u></em><em><u>C</u></em><em><u>Y</u></em><em><u>+</u></em><em><u>Y</u></em><em><u>A</u></em>
<em><u>c</u></em><em><u>a</u></em><em><u> </u></em><em><u>k</u></em><em><u>o</u></em><em><u> </u></em><em><u>c</u></em><em><u>o</u></em><em><u>m</u></em><em><u>m</u></em><em><u>a</u></em><em><u>n</u></em><em><u> </u></em><em><u>l</u></em><em><u>i</u></em><em><u>y</u></em><em><u>a</u></em><em><u> </u></em><em><u> </u></em><em><u>j</u></em><em><u>o</u></em><em><u> </u></em><em><u>k</u></em><em><u>i</u></em><em><u> </u></em><em><u>uska squire </u></em><em><u>m</u></em><em><u>e</u></em><em><u> </u></em><em><u>l</u></em><em><u>i</u></em><em><u>y</u></em><em><u>a</u></em>
<em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u>n</u></em><em><u> </u></em>
<em><u>a</u></em><em><u>b</u></em><em><u>+</u></em><em><u>b</u></em><em><u>c</u></em><em><u>+</u></em><em><u>(</u></em><em><u>c</u></em><em><u>a</u></em><em><u> </u></em><em><u>k</u></em><em><u>o</u></em><em><u> </u></em><em><u>s</u></em><em><u>q</u></em><em><u>u</u></em><em><u>r</u></em><em><u>a</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>main liya</u></em><em><u>)</u></em><em><u> </u></em>
- <em><u>answer is</u></em><em><u> </u></em><em><u>AB + BC</u></em><em><u> e + c</u></em><em><u>a</u></em><em><u> ka square</u></em><em><u> </u></em><em><u>plus AC is equals to</u></em><em><u> C</u></em><em><u>y</u></em><em><u>+</u></em><em><u> </u></em><em><u>y</u></em><em><u>a</u></em>