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MAXImum [283]
3 years ago
14

What is the kinetic Energy of a camion of 5,000 kg and turn at 100km/h ?

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0

Step-by-step explanation:

Given

mass (m) = 5000 kg

velocity (v) = 100 km/h = 100* 1000/ 3600 = 27.78m/s

Now

Kinetic energy

= 1/2 mv²

= 1/2 * 5000 * 27.78²

= 1929321 joule

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Please help with number 9.
RUDIKE [14]

Answer:

7,200

Step-by-step explanation:

5,900-4,700=1200 then 1200×6, 6 for 2016, equals 7,200

6 0
3 years ago
Sandy does babysitting in her spare time. She gets $100 advance pay and $10 per hour for babysitting. She wants to earn enough t
hoa [83]

Answer: 35 hours

Step-by-step explanation: 450-100 because of the advanced pay, then you dived 350 by ten so you get 35 hours

8 0
3 years ago
Read 2 more answers
Suppose management could improve the process by reducing the mean time required for an oil change (but keeping the standard devi
Alja [10]

This question is incomplete, the complete question is;

The owners of Spiffy Lube want to offer their customers a 10-minute guarantee on their standard oil change service. If the oil change takes longer than 10 minutes to complete, the customers is given a coupon for a free oil change at the next visit. Based on past history, the owners believe that the timer required to complete an oil change has a normal distribution with a mean of 8.6 minutes and a standard deviation of 1.2 minutes.

Suppose management could improve the process by reducing the mean time required for an oil change (but keeping the standard deviation the same). How much change in the mean service time would be required to allow for a 10-minute guarantee that gives a coupon to no more than 1 out of every 25 customers on average

Answer:

Required change in the mean service time is 7.8988

Step-by-step explanation:

Given the data in the question;

How much change in the mean service time would be required to allow for a 10-minute guarantee that gives a coupon to no more than 1 out of every 25 customers on average

let mean = μ

p( x > 10 ) ≤ (1/25)

p( x > 10 ) ≤ 0.4

p( x-μ / 1.2  > 10-μ / 1.2 ) ≤ 0.4

(10-μ / 1.2 ) ≤ 0.4

(10-μ / 1.2 ) ≥ q_{norm} ( 0.96 )

(10-μ / 1.2 ≥ 1.751

10-μ  = ≥ 1.751 × 1.2

10-μ  ≤ 2.1012

μ ≤ 10 - 2.1012

μ ≤ 7.8988

Therefore, required change in the mean service time is 7.8988

8 0
3 years ago
Which is a related facts 5+3=8 3+5=8 8-5
AleksandrR [38]
8-3=5 or 8-5=3

Is that what your looking for?
8 0
3 years ago
How do you do these 2 problems?
Varvara68 [4.7K]
The first question:
3X+Y=-1
Y=-3X-1     Y=-1/2X-7/2
-3X-1=-1/2X-7/2
-2.5X=-2.5
x=1
So the answer should be option B.
The last question:
Same thing , 
-1/2X-1=-3X+4
2.5X=5
X=2
So the answer is option B.
Those are your answers.

4 0
3 years ago
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