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3 years ago

Worth 12 Points, i spent 24

Mathematics

1 answer:

rewona [7]3 years ago

6 0

Answer:

$\displaystyle m^{\frac{35}{12}}n^{-\frac{28}{15}}=\frac{m^{\frac{35}{12}}}{n^{\frac{28}{15}}}$

Step-by-step explanation:

The relevant rule of exponents is ...

(a^b·c^d)^e = a^(be)·c^(de)

Then ...

(m^(5/4)·n^(-4/5))^(7/3) = m^(5/4·7/3)·n^(-4/5·7/3)

= m^(35/12)·n^(-28/15)

Since you want positive rational exponents, you can write this as ...

= m^(35/12)/n^(28/15)

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4 years ago

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