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3 years ago

If f(x)=x^+5x+2, find (-4) A) 34 B) -2 C) 38 D) -6

Mathematics

1 answer:

Ahat [919]3 years ago

8 0

Answer:

f(-4)= -2

Step-by-step explanation:

f(x)=x^2+5x+2 find(-4)

replace x= -4 in function

f(-4) = (-4)^2+ 5*-4+2

= 16 -20 +2

= 18-20

= -2

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X decreased by 61% I need the right answer

nataly862011 [7]

Answer:

X-61=100

X=100-61

X=39%

Step-by-step explanation:

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3 years ago

Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).

Reil [10]

Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) $sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}$

Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sin(\alpha)=cos(\beta)$

Find the value of $sin(\alpha)$ in the right triangle of the figure

$sin(\alpha)=\frac{8}{14}$ ---> opposite side divided by the hypotenuse

simplify

$sin(\alpha)=\frac{4}{7}$

therefore

$sin(\alpha)=\frac{4}{7}$

$cos(\beta)=\frac{4}{7}$

Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$tan(\alpha)=cot(\beta)$

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

$14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132$

$x=\sqrt{132}\ units$

simplify

$x=2\sqrt{33}\ units$

Find the value of $tan(\alpha)$ in the right triangle of the figure

$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

$tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) Find $sec(\alpha)\ and\ csc(\beta)$

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sec(\alpha)=csc(\beta)$

Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

Find the value of $cos(\alpha)$

$cos(\alpha)=\frac{2\sqrt{33}}{14}$ ---> adjacent side divided by the hypotenuse

simplify

$cos(\alpha)=\frac{\sqrt{33}}{7}$

therefore

$sec(\alpha)=\frac{7}{\sqrt{33}}$

$csc(\beta)=\frac{7}{\sqrt{33}}$

6 0

3 years ago

What is the square root of 64 multiplied by 2

Tamiku [17]

Answer:

its 16

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Step-by-step explanation:

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3 years ago

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tino4ka555 [31]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

(Order is anti-symmetric) If a > b and b > a, then a = b. (e) a

kirill115 [55]

Answer:

a=b

Step-by-step explanation:

An antisymmetric relation () satisfies the following property:

If (a, b) is in R and (b, a) is in R, then a = b.

This means that if a|b and b|a then a = b

If a|b then, b can be written as b = an for an integer n

If b|a then a can be written as a= bm for an integer m

Now we have b = (a)n = (bm)n

b = bmn

1 =mn

But since m and n are integers, the only two integers that satisfy this property would be m = n = 1

Therefore, b = an = a (1) = a ⇒b = a

5 0

3 years ago