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Anton [14]
3 years ago
14

If f(x)=x^+5x+2, find (-4) A) 34 B) -2 C) 38 D) -6

Mathematics
1 answer:
Ahat [919]3 years ago
8 0

Answer:

f(-4)= -2

Step-by-step explanation:

f(x)=x^2+5x+2 find(-4)

replace x= -4 in function

f(-4) = (-4)^2+ 5*-4+2

       = 16 -20 +2

       = 18-20

       = -2

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X decreased by 61% I need the right answer
nataly862011 [7]

Answer:

X-61=100

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X=39%

Step-by-step explanation:

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Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).​
Reil [10]

Answer:

Part A) sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}

Part B) tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}

Part C) sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}

Step-by-step explanation:

Part A) Find sin(\alpha)\ and\ cos(\beta)

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

sin(\alpha)=cos(\beta)

Find the value of sin(\alpha) in the right triangle of the figure

sin(\alpha)=\frac{8}{14} ---> opposite side divided by the hypotenuse

simplify

sin(\alpha)=\frac{4}{7}

therefore

sin(\alpha)=\frac{4}{7}

cos(\beta)=\frac{4}{7}

Part B) Find tan(\alpha)\ and\ cot(\beta)

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

tan(\alpha)=cot(\beta)

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132

x=\sqrt{132}\ units

simplify

x=2\sqrt{33}\ units

Find the value of tan(\alpha) in the right triangle of the figure

tan(\alpha)=\frac{8}{2\sqrt{33}} ---> opposite side divided by the adjacent side angle alpha

simplify

tan(\alpha)=\frac{4}{\sqrt{33}}

therefore

tan(\alpha)=\frac{4}{\sqrt{33}}

tan(\beta)=\frac{4}{\sqrt{33}}

Part C) Find sec(\alpha)\ and\ csc(\beta)

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

sec(\alpha)=csc(\beta)

Find the value of sec(\alpha) in the right triangle of the figure

sec(\alpha)=\frac{1}{cos(\alpha)}

Find the value of cos(\alpha)

cos(\alpha)=\frac{2\sqrt{33}}{14} ---> adjacent side divided by the hypotenuse

simplify

cos(\alpha)=\frac{\sqrt{33}}{7}

therefore

sec(\alpha)=\frac{7}{\sqrt{33}}

csc(\beta)=\frac{7}{\sqrt{33}}

6 0
3 years ago
What is the square root of 64 multiplied by 2
Tamiku [17]

Answer:

its 16

as we know the square root of 64 is 6 and when it is multiplied by 2 its answer is 16.

Step-by-step explanation:

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tino4ka555 [31]

Answer:

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Step-by-step explanation:

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(Order is anti-symmetric) If a &gt; b and b &gt; a, then a = b. (e) a
kirill115 [55]

Answer:

a=b

Step-by-step explanation:

An antisymmetric relation () satisfies the following property:

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This means that if a|b and b|a then a = b

If a|b then, b can be written as b = an for an integer n

If b|a then a can be written as a= bm for an integer m

Now we have b = (a)n = (bm)n

b = bmn

1 =mn

But since m and n are integers, the only two integers that satisfy this property would be m = n = 1

Therefore, b = an = a (1) = a ⇒b = a

5 0
3 years ago
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