The value of the function h(x + 1) is -x^2 - x + 1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(x + 1)
This means that t = x + 1
So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1
h(x + 1) =-(x + 1)^2 + (x + 1) + 1
Evaluate the exponent
h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1
Expand the brackets
h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1
Evaluate the like terms
h(x + 1) = -x^2 - x + 1
Hence, the value of the function h(x + 1) is -x^2 - x + 1
Read more about functions at:
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(x + 1)
Answer:
C - Triangle, Pentagon, Hexagon, Decagon
Step-by-step explanation:
Triangle - 3 sides
Pentagon - 5 sides
Hexagon - 6 sides
Decagon - 10 sides
From Least to greatest!
:)
x^2 + 10x = - 5
To complete the square, we need to add a constant on the
left side that makes the expression on the right a perfect square trinomial. We
need to add the same value on the right side to keep the equation equal. So,
x^2 + 10x + a = -5 + a
where a is the square of one-half the coefficient of x, therefore:
a = (10 / 2)^2 = 25
x^2 + 10x + 25 = -5 + 25
(x + 5)^2 = 20
Taking the square root of both sides:
x + 5 = ± 4.47
x = -5 ± 4.47
<span>x = -9.47, -0.53</span>
Answer:
slope is 5, y intercept is -7
Step-by-step explanation:
In the form y=mx+c, m is the slope and c is the y-intercept.
Rearrange the formula to fit this form:
5x-y=7
-y=7-5x
y=5x-7
∴m(slope)=5
∴c(y-intercept)=-7
Answer:
B
Step-by-step explanation:
Hope it helps and if you need explanation let it in the comments