3/4
9/10 times 5/6= 45/60 divide by 3 then divide by 5. 15/20 = 3/4
Answer:
(2x+5y)(2x+3y)
=(2x)^2 + [5y+3y]2x + (5y)(3y)
=4x^2 +16xy + 15y^2
Step-by-step explanation:
Answer:
B)12
Step-by-step explanation:
![\frac{16}{f}=\frac{12}{9}\\\\16*9=12*f\\\\\frac{16*9}{12}=f\\\\ 4*3=f\\\\f=12](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7Bf%7D%3D%5Cfrac%7B12%7D%7B9%7D%5C%5C%5C%5C16%2A9%3D12%2Af%5C%5C%5C%5C%5Cfrac%7B16%2A9%7D%7B12%7D%3Df%5C%5C%5C%5C%204%2A3%3Df%5C%5C%5C%5Cf%3D12)
Answer:
a) 25 feet
b) Base width 23.57 feet
Step-by-step explanation: The expression:
h(x) = -0,18*x² + 25
is a quadratic function ( a parable). as a < 1 open down
The vertex of the parable is V(x,y)
a) V(x) = - b/2a = 0/2a V(x) = 0 to find V(y) we make use of the original equation and plugging x = 0
y = - 0.18*x² + 25 ⇒ y = 0 + 25 ⇒ y = 25
The Vertex is V ( 0 , 25 )
Now vertex in this case is the maximum height.
h(max) = 25 feet
b) To find how wide is the base of the tunnel. We have to consider that for h = 0 we are at ground level therefore the two roots of the quadratic equation will give the wide of the base of the tunnel
Then
h (x) = -018*x² +25 ⇒ 0 = -018*x² +25 ⇒ x² = 25/0.18
x² = 138.89
x = ± 11.79 ft
So we found interception with x axis and wide of the base is
2 * 11.79 = 23.57 feet