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FromTheMoon [43]
3 years ago
14

2/3*5 6*8 simplified please help

Mathematics
1 answer:
vivado [14]3 years ago
6 0
I am assuming that this is 2/3*5*6*8...

Answer: 160


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A candle in the shape of a circular cone has a base of radius r and a height of h that is the same length as the radius. which e
ladessa [460]

Answer:

\frac{r(1-\sqrt{2})}{-3}

Step-by-step explanation:

Volume of cone = \frac{1}{3} \pi r^{2} h

Since we are given that a circular cone has a base of radius r and a height of h that is the same length as the radius

                          = \frac{1}{3} \pi r^{2} \times r

                          = \frac{1}{3} \pi r^{3}

Surface area of cone including 1 base = \pi r^{2} +\pi\times r \times \sqrt{r^2+h^2}

Since r = h

So, area = \pi r^{2} +\pi\times r \times \sqrt{r^2+r^2}

              = \pi r^{2} +\pi\times r \times \sqrt{2r^2}

              = \pi r^{2} +\pi\times r^2 \times \sqrt{2}

Ratio of volume of cone to its surface area including base :

\frac{\frac{1}{3} \pi r^{3}}{\pi r^{2} +\pi\times r^2 \times \sqrt{2}}

\frac{\frac{1}{3}r}{1+\sqrt{2}}

\frac{r}{3(1+\sqrt{2})}

Rationalizing

\frac{r}{3(1+\sqrt{2})} \times \frac{1-\sqrt{2}}{1-\sqrt{2}}

\frac{r(1-\sqrt{2})}{-3}

Hence the ratio the ratio of the volume of the candle to its surface area(including the base) is \frac{r(1-\sqrt{2})}{-3}

8 0
3 years ago
Read 2 more answers
Three more than eight times a number is equal to 19
djverab [1.8K]
19-3=16
16/8=2
2x8+3=19
The answer is 2.
8 0
3 years ago
Read 2 more answers
_16. Which expression is equivalent to
Phantasy [73]

Answer:

-2x-8

Step-by-step explanation:

1) Distribute:

-6/3x+-15/3-3

2) Simplify:

-2x-5-3

3) combine like terms:

-2x-8

hope this helps

5 0
3 years ago
Write the statement in if-then form.
Vilka [71]
I believe the answer is A because its the only one that makes the most sense.
4 0
2 years ago
Read 2 more answers
Find the area of a kite with diagonals 15 m and 7 m.​
lozanna [386]

Answer:

<h2>A = 52.5 m²</h2>

Step-by-step explanation:

The formula of an area of a kite:

A=\dfrac{e\cdot f}{2}

<em>e, f</em><em> - diagonals</em>

<em />

We have <em>e = 15m, f = 7m.</em>

Substitute:

A=\dfraC{(15)(7)}{2}=\dfrac{105}{2}=52.5\ m^2

3 0
3 years ago
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