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2 years ago

A hiker walks at a speed of 3 2 5 kilometers per hour. How many kilometers will the hiker walk-in

Mathematics

2 answers:

denis-greek [22]2 years ago

4 0

Answer:

18.75km

Step-by-step explanation:

All you have to do is multiply the average speed times the time, in this case 5 hours. So it will look like this: 3 3/4x5.

Solve that, and you get 18.75 km. (in decimal form)

Hope that helps! Have a great day.

Leto [7]2 years ago

3 0

Answer:

65 km

Step-by-step explanation:

was that 325 km? if so it would be 325 x 5 = 65

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Jack is 4 times as old as lacey. 7 years ago the sum of their age was 61. how old are they now?

BaLLatris [955]

I am guessing Jack is 51 and Lacey is 17.

7 0

2 years ago

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species

kotegsom [21]

Answer:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

Step-by-step explanation:

The logistic equation is the following one:

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that $P(0) = 80, K = 2000$ .

The number of fish tripled in the first year. This means that $P(1) = 3P(0) = 3(80) = 240$ .

Using the equation for P(1), that is, P(t) when $t = 1$ , we find the value of r.

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

$240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}$

$280*(2000 + 80(e^{r} - 1)) = 160000e^{r}$

$280*(2000 + 80e^{r} - 80) = 160000e^{r}$

$280*(1920 + 80e^{r}) = 160000e^{r}$

$537600 + 22400e^{r} = 160000e^{r}$

$137600e^{r} = 537600$

$e^{r} = \frac{537600}{137600}$

$e^{r} = 3.91$

Applying ln to both sides.

$\ln{e^{r}} = \ln{3.91}$

$r = 1.36$

This means that the expression for the size of the population after t years is:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

4 0

2 years ago

The price of a cellular telephone plan is based on peak and nonpeak service. Kelsey used 45 peak minutes and 50 nonpeak minutes

Oxana [17]

We can build a system of two linear equations with two unknowns with the info provided in the problem, one with Kelsey info and one with Mitch info like so:
Lets call p the amount on peak minutes and n the amount of non-peak minutes:
45p + 50n = 27.75
70p + 30n = 36
lets reduce the equations dividing the first by 5:
9p + 10n = 5.55
70p + 30n = 36
now, to eliminate n, lets multiply the first equation by -3 and add the two equations:
-27p - 30n = -16.65
70p + 30n = 36
----------------------------
43p + 0 = 19.35
p = 19.35/43
p = 0.45
therefore the peak rate is $0.45 per minute
lets substitute in one of the original equations this result:
45p + 50n = 27.75
45(0.45) + 50n = 27.75
20.25 + 50n = 27.75
50n = 27.75 - 20.25
50n = 7.5
n = 7.5/50
n = 0.15
therefore the non-peak rate per minute is $0.15

5 0

2 years ago

A rectangular birthday present, 3 in. by 7 in. by 8 in., is covered by wrapping paper. How much wrapping paper is required

madam [21]

2 x (7 x 3) + 2 x (8 x 7) + 2 x (8 x 3)

4 0

2 years ago

I need help with this please

Vinvika [58]

Answer:

Step-by-step explanation:

7x6

5 0

2 years ago