Math 8th grade. 40 pts.
2 answers:
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Answer:
and
.
Step-by-step explanation:
So I believe the problem is this:
where we are asked to find values for and
such that the equation holds for any
in the equation's domain.
So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).
In other words this will clear the fractions.
As you can see there was some cancellation.
I'm going to plug in -7 for x because x+7 becomes 0 then.
Divide both sides by -10:
Now we have:
with
I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.
Divide both sides by 10:
So and
.
Answer:
p =
Step-by-step explanation:
Given that p varies inversely with q then the equation relating them is
p = ← k is the constant of variation
To find k use the condition p = 2 when q = 1, thus
k = pq = 2 × 1 = 2
p = ← equation of variation