Multiply the length and width together:
3 2 6
A = ------ * ------ = --------
5 5 25
None of the given possible answers make any sense. Please ensure that you have copied down this problem exactly as presented.
If the width were 2/5 in and the length 3/5 in, then, using decimal fractions, the area would be
A = 0.4(0.6) = 0.24 in^2, which is miles and miles away from 15 in^2 (for example)
Answer:
Step-by-step explanation:
Given 
Let 
Interchange x and y
Solve for y, by first squaring both sides
Hence
The last choice is correct
Anything withdrawn you subtract. Then, you know the total and you know what you had. Subtract total from what you had and you will see the change.
1735.97-100=1635.97
1668.71-1635.97=32.74
