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goblinko [34]
3 years ago
13

Please help I’m timed!!

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
8 0

Answer:

5/9, 2/7, 3/10 are all rational numbers

Step-by-step explanation:

Remember that all rational numbers are able to be written as a fraction or ratio of two integers.

Marysya12 [62]3 years ago
3 0

Answer:

\frac{2}{7}+\sqrt{121}

Step-by-step explanation:

Since, a real number is called rational number if it can be expressed in the form of \frac{p}{q},

Where, p and q are integers,

S.t. q ≠ 0,

If the number is not a rational number then it is irrational,

Now, the sum or difference of two rational numbers is a rational number,

While, the sum or difference of a rational number and an irrational number is an irrational number.

∵ √18, √11 and \pi are irrational numbers,

Also, \frac{5}{9}, \sqrt{16} and \frac{3}{10} are rational number,

\implies \frac{5}{9}+\sqrt{18},\pi+\sqrt{16}, \frac{3}{10}+\sqrt{11}\text{ are irrational numbers}

Now,

\frac{2}{7}\text{ and }\sqrt{121}\text{ are rational numbers}

Hence,

\frac{2}{7}+\sqrt{121}\text{ is rational number}

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Step-by-step explanation:

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g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds
dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

The number of ways of selecting 3 cards from 13 clubs is:

{13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286

The number of ways of selecting 5 cards from 13 diamonds is:

{13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287

The number of ways of selecting 0 cards from 13 spades is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

Compute the number of ways to select 5 diamonds and 3 clubs as:

{13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0
2 years ago
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