Answer:
The standard deviation of a probability distribution is a measure of variability of the distribution.
Step-by-step explanation:
We have been given an incomplete statement. We are asked to complete the given statement.
We know that standard deviation is measure of variability or dispersion of a set of data values.
It tells up how much a data point is spread out from the average or mean of the data set.
Therefore, option A is the correct choice.
Answer:
The domain of the graph must be 
.
Therefore,
Hence, option a is true.
Step-by-step explanation:
From the graph, it is clear that the graph is heading towards positive infinity from x=-4.
The point x=-4 is included in the graph as the starting point of the graph i.e. x=4 is showing a closed circle on x=4, and heading towards positive infinity onward.
i.e. [-4, ∞)
Hence, the domain of the graph must be .
Therefore,
Hence, option a is true.
Answer:
Assuming 1/20 is a 5% late fee:
$21.211
Step-by-step explanation:
67.82 x 1/20 = 3.391
67.82 + 3.391 = 71.211
Answer:
Step-by-step explanation:
Slope-intercept form equation is given as 
Where,
y = distance remaining
x = hours driven
m = slope/constant rate. In this case, the value of m would be -65. This means the distance will reduce at a constant rate of 65 miles per hour.
b = y-intercept, which is the initial value or the distance between the cities = 420
Plug in the values into the slope-intercept equation, to represent the distance y in miles remaining after driving x hours. You would have:
Answer:
Rhea's estimation is unreasonable.
Step-by-step explanation:
Identify what you know:
1) Rhea calculates that she can write 1.25 pages every 2 hours
2) Rhea is calculating how long it would take her to write 6 pages.
Using Rhea's initial calculation, we can figure out roughly, how long it would take her to finish 6 pages.
First we need to divide 6 by 1.25, to figure out how many "2 hour" periods it would take Rhea.
6/1.25 = 4.8
4.8 x 2 = 9.6
It would take Rhea roughly 9.6 hours to finish 6 pages, which is 3.6 hours more than her original estimation. Thus, her estimate is unreasonable.
