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Ksenya-84 [330]
3 years ago
15

What are the solutions to the quadratic equation below x^2+20x+100=7​

Mathematics
1 answer:
aleksandrvk [35]3 years ago
7 0

First you must have the quadratic equal to zero. In order to do this you must subtract 7 to both sides

x^2 + 20x + (100 - 7) = 7 - 7

x^2 + 20x + 93 = 0

Now you must find two numbers who's sum equals 20 and their multiplication equal 93

Are there any? NO!

This means that you have to use the formula:

\frac{-b±\sqrt{b^{2} - 4ac} }{2a}

In this case:

a = 1

b = 20

c = 93

\frac{-(20) plus/minus\sqrt{20^{2} - 4(1)(93)} }{2*1}

\frac{-20 plus/minus\sqrt{400 - 372} }{2}

\frac{-20 plus/minus\sqrt{28} }{2}

^^^We must simplify √28

√28 = 2√7

so...

\frac{-20 plus/minus 2\sqrt{7} }{2}

simplify further:

-10 plus/minus\sqrt{7

-10 + √7

or

-10 - √7

***plus/minus = ±

Hope this helped!

~Just a girl in love with Shawn Mendes

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Answer:

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Step-by-step explanation:

Let's solve the operation given, this way:

(7 - 11/) + (-3 + 5/)

7 - 11 - 3 + 5=

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<u>After resolving the parenthesis, adding and subtracting the result of thhe operation is - 2</u>

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5 0
3 years ago
-2(bx-5)=16<br> The value of x in terms of b is?<br> That value of x when b is 3?
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Answer:

Step-by-step explanation:

Let's solve for b.

−2(bx−5)=16

Step 1: Add -10 to both sides.

−2bx+10+−10=16+−10

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Step 2: Divide both sides by -2x.

−2bx/−2x=6/−2x

b=−3x

Answer:

b=−3x

———————————————————

Let's solve for x.

−2(bx−5)=16

Step 1: Add -10 to both sides.

−2bx+10+−10=16+−10

−2bx=6

Step 2: Divide both sides by -2b.

−2bx/−2b=6/−2b

x=−3b

Answer:

x=−3b

Hope this helps you out

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