In this item, we are given that the number of miles that John runs every day vary. Therefore, it is just rightful that we use three different variables for the number of miles he ran for three days. For the purpose of representation in this item, we let the variables be x, y, and z. The total miles he ran is equal to the sum of the three variables. Let T be the total and that would be equal to,
<em> T = x + y + z</em>
Answer:
10 km/h
Step-by-step explanation:
I'm not really sure about this but no ones answering your question and I wanna help.
So basically to calculate the average speed you need to divide the distance travelled by time taken
But you do not have the distance traveled. But it is mentioned that it takes u 30 minutes to walk from home to school when walking at 5 km/h so to find the distance all you have to do is... 30 x 5 = 150 km
Now that we have the time and distance all we have to do is find the average speed.
Average Speed = distance ÷ time
So 150 ÷ 15 = 10 km/h
Answer: IX - 4I ≤ 4
Step-by-step explanation:
In the numer line we can see that our possible values of x are in the range:
0 ≤ x ≤ 8
And we want to find an absolute value equation such that this set is the set of possible solutions.
An example can be:
IX - 4I ≤ 4
To construct this, we first find the midpoint M of our set, in this case is 4.
Then we write:
Ix - MI ≤ IMI
Notice that i am using the minor and equal sign, this is because the black dots means that the values x = 0 and x = 8 are included, if the dots were empty dots, it would be an open set and we should use the < > signs.
Answer: 32.35 cm^2
Step by step:
Find the area of the rectangle first.
A= L • W
A= 11 • 4.2
A= 46.2 cm^2
Then find the area of the circle. The formula is A= pi (r)^2. The diameter of the circle is 4.2 cm because looking at the width of the rectangle it fits into the circle as well.
Half of the diameter is 2.1 cm which is the radius.
A= pi (r)^2
A= pi (2.1)^2
A= pi (4.41)
A= 13.85 cm^2
Then you would subtract 13.85 from 46.2 to find the shaded portion.
Hope this helps :))
I don’t see a expression...
