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slega [8]
3 years ago
14

Which ordered pair is the solution to the system of equations below? 4x+3y=31 2y=22-3x (A) (4,5) (B) (5,4) (C) (6,2) (D) (7,1)

Mathematics
1 answer:
grandymaker [24]3 years ago
5 0

Plug in the points x and y

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casey has a small business making dessert baskets. she estimates that her fixed weekly costs for rent, electricity, and salaries
m_a_m_a [10]
500 = 200 + 2.50x
x = amount of dessert baskets

500 - 200 = 300.
300 = 2.50x
300 ÷ 2.50 = 120.
Casey made 120 dessert baskets.
3 0
3 years ago
The diameter of a quarter is 2.5 cm. What is it’s circumference?
anastassius [24]

Answer:

7.85 cm

Step-by-step explanation:

The circumference of a circle can be found using the following formula.

c=\pi d

The diameter is 2.5 centimeters. Therefore, we can substitute 2.5 cm in for d.

c=\pi *2.5 cm

Now, find the circumference.

- In terms of pi:

c=\pi *2.5 cm

c= (2.5)\pi  cm

c= 2.5\pi  cm

-Using 3.14 as pi

c=\pi *2.5 cm

c=3.14 *2.5 cm

c=7.85 cm

-Using 3.14159... as pi

c=\pi *2.5 cm

c=7.85398163 cm

7 0
3 years ago
Stretch your thinking rewrite this sentence using the word fewer: Carey reads 10 more pages than Lucey .
Free_Kalibri [48]
Lucy read 10 fewer pages than Carey
5 0
3 years ago
Simplify 2√2-√3<br> ---------------<br> √2+√3
serious [3.7K]

Step-by-step explanation:

=  \frac{2 \sqrt{2}   -  \sqrt{3} }{ \sqrt{2} +  \sqrt{3}  }

=  \frac{2 \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} +  \sqrt{3}  }  \times  \frac{ \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} -  \sqrt{3}  }

= \frac{ 2( \sqrt{2}  -  \sqrt{3} )( \sqrt{2}  -  \sqrt{3} )}{ { \sqrt{2} }^{2} -  { \sqrt{3} }^{2}  }

=  \frac{2(2 -  \sqrt{6}  -  \sqrt{6} - 3) }{2 - 3}

=  \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}

=  \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}

= 2(1 + 2 \sqrt{6} )

= 2 + 4 \sqrt{6}

6 0
2 years ago
A function of the form f(x)=mc+b, where m and b are real numbers is called a ____ function ?
FrozenT [24]
You mean f(x) = my+ b
This is called slope
7 0
3 years ago
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