Answer:
Let b=x
Such that b^2 =8b-8 will x^2=8x-8
Using the almighty quadratic formula
x1={-b+sqrt (b^2-4ac)}/2a
x2={-b-sqrt (b^2-4ac)}/2a
From the question
a=1
b=8
c=-8
x1={-8+sqrt (8^2-4(-8))}/2
x1=(-8+5.66)/2
x1=-1.17
x2={-8-sqrt (8^2-4(-8))}/2
x2=(-8-5.66)/2
x2=-6.83
:.(x1,x2)=(-1.17,-6.83)
Step-by-step explanation:
38-15= 23. I’m guessing this is what you meant. If not please correct me.
Answer:
No answer
Step-by-step explanation:
5x-20-X+9
7x-20+9
7x-11
Answer:
<h2>
Step-by-step explanation:</h2><h2>|(5x-4)-3|<0.01</h2><h2>so -0.01<(5x-4-3)<0.01</h2><h2>add 7</h2><h2>7-0.01<5x<7+0.01</h2><h2>6.99<5x<7.01</h2><h2>divide by 5</h2><h2>1.398<x<1.402</h2>