T = 20 % : 20 / 100 = 0.2
m1 = solute
m2 = Solvent
T = m1 / m1 + m2
0.2 = 500 g / 500 g + m2
0.2 * ( 500 + m2 ) = 500
0.2 * 500 + 0.2 m2 = 500
100 + 0.2 m2 = 500
0.2 m2 = 500 - 100
0.2 m2 = 400
m2 = 400 / 0.2
m2 = 2000 g of water
hope this helps!
Answer:
Trial 2, because the amount of product formed per unit time is higher.
Explanation:
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Explanation:
Ph=14-4.23
Ph=9.77
Its a Base because bases have high Ph and acids have low ph
The complete question is;
How many Joules of heat energy would be required to raise the temperature of 16.0 g of lead from 25 degrees to its melting point of 327 degrees for a length of time long enough to completely melt the lead.
Specific heat capacity of lead is 0.159 J/gK and the molar enthalpy of fusion is 24.7 J/g
Heat is given by mcΔT
Δ T= 322 ° c = 322 +273 = 595 K
Heat = (16 × 595 × 0.159) + (24.7 × 16 )
= 1513.68 + 395.2
= 1908.88 Juoles