1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KATRIN_1 [288]
3 years ago
13

To make a 3.50 M solution, how many moles of solute will be needed if 11 liters of solution are required?

Chemistry
2 answers:
never [62]3 years ago
5 0

Answer:

To make a 3.50 M solution, 38.5 moles of solute will be needed if 11 liters of solution are required.

Explanation:

Molarity is defined as a concentration unit that indicates the number of moles of solute per liter of solution. That is, it indicates the number of moles of solute that are dissolved in a given volume. Then, the molarity is calculated by dividing the moles of the solute by the liters (volume) of the solution:

Molarity( M)=\frac{number of moles of solute}{volume}

Molarity is expressed in units (\frac{moles}{liter}).

So, knowing the definition of molarity, you can apply a rule of three as follows: if by the definition of molarity in 1 L of solution there are 3.5 moles of solute, in 11 L of solution how many moles of solute are there?

moles=\frac{11 L*3.5 moles}{1L}

moles=38.5

<u><em>To make a 3.50 M solution, 38.5 moles of solute will be needed if 11 liters of solution are required.</em></u>

<u><em></em></u>

hodyreva [135]3 years ago
3 0

Answer:

The number of moles is 38.5 moles

Explanation:

Given:

Concentration of the solution = 3.5 M

Volume of solution = 11 L

Question: How many moles of solute, nsol = ?

The molarity is the number of moles of the solute divided by the volume of the solution, in this case:

n_{sol} =Molarity*Volume=3.5\frac{mol}{L} *11L=38.5moles

You might be interested in
6. Write the ICE chart for the reaction of 32.0 g of sulfur and 71.0 g of chlorine: S8 + 4 Cl24S2Cl2 After completing the chart
Marianna [84]

Answer:

ICE Table Figure

a. 67.37 g S_2Cl_2

b. 35.62 g Cl_2

c. 58.61 gS_2Cl_2

Explanation:

For the <u>ICE table </u>we have to keep in mind that we have 4 moles of Cl_2 and 1 mol of S_8 and the reactives are consumed, so for Cl_2 we will have -4X and for S_8 we will have -X. Follow the same logic we will have -4X for S_2Cl_2.

a. <u>Mass of the product</u>

Molar mass of S_8= 256.52 g/mol

Molar mass of Cl_2=70.9 g/mol

Molar mass of S_2Cl_2=135.03 g/mol

We have to find the limiting reagent in the reaction:

S_8+4Cl_2->4S_2Cl_2

\frac{32}{256.52}=0.124molS_8

\frac{71}{70.9}=1 molCl_2

Divide by the coefficients in the balanced reaction:

\frac{0.124}{1}=0.124mol

\frac{1}{4}=0.25 mol

The limiting reagent would be S_8

Now is posible to calculate the amount of S_2Cl_2 produced:

0.124molS_8\frac{4molS_2Cl_2}{1 molS_8}\frac{135.03gS_2Cl_2}{1 molS_2Cl_2}=67.37gS_2Cl_2

b. <u>Mass  in excess</u>

0.124molS_8\frac{4molCl_2}{1 molS_8}\frac{70.9gCl_2}{1 molCl_2}=35.38gCl_2

Excess\hspace{0.1cm}=\hspace{0.1cm}71gCl_2-35.38gCl_2=35.62 gCl_2

C. <u>87%Yield</u>

67.37gS_2Cl_2\frac{87}{100}=58.61gS_2Cl_2

5 0
3 years ago
In a diamond, what type of bonds link carbon atoms together to form a network solid?
never [62]

The answer is covalent bond

5 0
3 years ago
Cu(NO3)2 + Zn (s) → Cu (s) + Zn(NO3)2 is an example of which type of reaction?
labwork [276]
Single replacements since cu is being replaced by zn
4 0
4 years ago
Calculate the pH of a buffer solution created by reacting 100 mL of 0.1 M NH3 with 90 mL of 0.1 M HNO3. (Remember, you can find
algol13

This question is asking for the pH of a buffer solution between ammonia and nitric acid, with given volumes and concentrations. At the end, the result turns out to be 10.488.

<h3>Buffers</h3>

In chemistry, buffers are known as substances attempting to hold a relatively constant pH by mixing and acid and a base (weak and strong). In such a way, for the substances given, the first step will be to calculate the consumed moles as they are mixed:

n_{NH_3}=0.1L*0.1mol/L=0.01mol\\\\n_{HNO_3}=0.09L*0.1mol/L=0.009mol

Now, since ammonia is in a greater proportion, one can calculate how much of it is left after being consumed by the nitric acid:

n_{NH_3}^{left}=0.01mol-0.009mol=0.001mol

And its new concentration:

[NH_3]=\frac{0.001mol}{0.1L+0.09L} =0.00526M

Next, with ammonia's ionization:

NH_3+H_2O\rightleftharpoons NH_4^++OH^-

We set up the equilibrium expression based on ammonia's Kb:

Kb=\frac{[NH_4^+][OH^-]}{[NH_3]}

Which can be solved by introducing x and using ammonia's Kb:

1.8x10^{-5}=\frac{x^2}{0.00526M}\\ \\

Then, we solve for x which is also equal to the concentration of ammonium and hydroxide ions in the solution:

x=\sqrt{0.00526*1.8x10^{-5}}=0.000308M

Ultimately, we calculate the pOH and then turn it into pH with:

pOH=-log(0.00308)=3.512\\\\pH=14-3.512=10.488

Learn more about buffers: brainly.com/question/24188850

6 0
2 years ago
If an element has more than one ionic charge, how is that piece of information represented in a chemical name?
solmaris [256]
Usually with roman numerals, like iron (II) chromate
iron has a charge of 2
or manganese (IV) oxide, manganese has a charge of 4
(these are ionic compounds just to let you know)
4 0
3 years ago
Other questions:
  • How many days pass until the exact same Moon shape reappears?
    10·1 answer
  • What is the purpose of determining melting points?
    11·1 answer
  • PLEASES HELP ASAP
    5·2 answers
  • Which statement best describes how chemical equations demonstrate conservation of mass?
    12·1 answer
  • In the Haber process for the production of ammonia, what is the relationship between the rate of production of ammonia and the r
    9·2 answers
  • A 25.0-mL solution of 0.100 M CH3COOH
    8·1 answer
  • An object has a mass of 4 grams and a volume of 2 cm3 what is the density of the object ​
    15·1 answer
  • Which of the following is something a school might dictate? *
    11·1 answer
  • When 240 mg of a certain molecular compound X are dissolved in 35.0 g of dibenzyl ether ((C6H5CH2)2O), the freezing point of the
    10·1 answer
  • Throughout the reflection, make sure you have a copy of the Student Guide and your data tables. Use the drop-down menus to compl
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!