Question

Hey can you please help me posted picture of question:)

Answer 1

We have the following equation:
 2x2-3x + 1
 Using resolver we have:
 x = (- b +/- root (b2-4ac)) / (2a)
 Substituting values we have:
 x = (- (- 3) +/- root ((- 3) 2-4 (2) (1))) / (2 (2))
 Rewriting:
 x = (3 +/- root (9-8)) / (4)
 x = (3 +/- root (1)) / (4)
 b2-4ac = 1> 0
 root(b2-4ac) = 1 < 3
 Answer:
 Two positive real solutions
 option C

Answer 2

Two positive roots.
the answer is C