We have the following equation: 2x2-3x + 1 Using resolver we have: x = (- b +/- root (b2-4ac)) / (2a) Substituting values we have: x = (- (- 3) +/- root ((- 3) 2-4 (2) (1))) / (2 (2)) Rewriting: x = (3 +/- root (9-8)) / (4) x = (3 +/- root (1)) / (4) b2-4ac = 1> 0 root(b2-4ac) = 1 < 3 Answer: Two positive real solutions option C