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g100num [7]
3 years ago
5

Human development begins with a(n)

Biology
2 answers:
hammer [34]3 years ago
5 0

Answer:

embryo and gametes

artcher [175]3 years ago
3 0

Answer:

Zygote, the nucleus of  male and female gametes join, mitosis

Explanation:

The human belongs to the animal kingdom which begins their life when the male and female gametes fuse through a process called Fertilization.

The process of fertilization involves the fusion of the nucleus or the genetic material of the male and female gametes. The process forms a diploid cellular structure called the zygote. After the formation of the zygote, the first cell division or mitosis produces the embryo which develops into an organism.

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PLZ HELP URGENT. WILL GIVE BRAINLIEST!!!!!
vlabodo [156]

Answer:

1. Asexual Reproduction (If there is only one organism reproducing)

2. Selective Breeding

Explanation:

1. If there is only one parent organism that means the offspring it is a carbon copy of its parent.

2. Selective breeding is breeding to bring out more desirable traits out of the species, like how dog breeders breed for better sense of smell or hearing.

8 0
3 years ago
Signals of a ________ include a blank stare, a period of distorted sensation and/or uncontrolled muscular contractions.
AysviL [449]
The answer in the space provided is seizure. The likely symptoms of it is mentioned above such as the blank stare, period of distorted sensations and uncontrollable muscular contractions. Seizure mostly occur when there is likely a sudden attack of an illness to a person, triggering him or her into a shock which is the seizures.
6 0
3 years ago
The primary electron acceptor in photosystem II is __________. Group of answer choices P700 P700 P680 P680
sesenic [268]

Answer:

680

Explanation:

When the P680 special pair of photosystem II absorbs energy, it enters an excited (high-energy) state. Excited P680 is a good electron donor and can transfer its excited electron to the primary electron acceptor, pheophytin.

7 0
2 years ago
A scientist performs an experiment in which they create an artificial cell with a selectively permeable membrane through which o
Alborosie

Answer:A. Water moves into the cell

Explanation:water moves into the cell through osmosis.during osmosis water moves from a region of low concentration of solute to a region of high concentration of solute.the glucose introduced into the cell makes it more concentrated.

In this case the cell is hypertonic and water would enter into the cell through the semi permeable membrane.this membrane allows water to pass through but not glucose.this movement of water into the cell causes the cell to become turgid.

3 0
4 years ago
Explain how we know that DNA breaks and rejoins during recombination.
alisha [4.7K]

Answer:

It occurs through homologous recombination

Explanation:

GENERAL RECOMBINATION OR HOMOLOGIST

           Previously we defined its general characteristics. We will now describe a molecular model of this recombination, based on the classic Meselson and Radding, modified with the latest advances. Do not forget that we are facing a model, that is, a hypothetical proposal to explain a set of experimental data. Not all points of this model are fully clarified or demonstrated:

           Suppose we have an exogenote and an endogenote, both consisting of double helices. In recombination models, the exogenote is usually referred to as donor DNA, and the endogenote as recipient DNA.

1) Start of recombination: Homologous recombination begins with an endonucleotide incision in one of the donor double helix chains. Responsible for this process is the nuclease RecBCD (= nuclease V), which acts as follows: it is randomly attached to the donor's DNA, and moves along the double helix until it finds a characteristic sequence called c

Once the sequence is recognized, the RecBCD nuclease cuts to 4-6 bases to the right (3 'side) of the upper chain (as we have written above). Then, this same protein, acting now as a helicase, unrolls the cut chain, causing a zone of single-stranded DNA (c.s. DNA) to move with its 3 ’free end

2) The gap left by the displaced portion of the donor cut chain is filled by reparative DNA synthesis.

3) The displaced single chain zone of the donor DNA is coated by subunits of the RecA protein (at the rate of one RecA monomer per 5-10 bases). Thus, that simple chain adopts an extended helical configuration.

4) Assimilation or synapse: This is the key moment of action of RecA. Somehow, the DNA-bound RecA c.s. The donor facilitates the encounter of the latter with the complementary double helix part of the recipient, so that in principle a triple helix is formed. Then, with the hydrolysis of ATP, RecA facilitates that the donor chain moves to the homologous chain of the receptor, and therefore matches the complementary one of that receptor. In this process, the chain portion of the donor's homologous receptor is displaced, causing the so-called "D-structure".

It is important to highlight that this process promoted by RecA depends on the donor and the recipient having great sequence homology (from 100 to 95%), and that these homology segments are more than 100 bases in length.

Note that this synapse involves the formation of a portion of heteroduplex in the double receptor helix: there is an area where each chain comes from a DNA c.d. different parental (donor and recipient).

5) It is assumed that the newly displaced chain of the recipient DNA (D-structure) is digested by nucleases.

6) Covalent union of the ends originating in the two homologous chains. This results in a simple cross-linking whereby the two double helices are "tied." The resulting global structure is called the Holliday structure or joint.

7) Migration of the branches: a complex formed by the RuvA and RuvB proteins is attached to the crossing point of the Holliday structure, which with ATP hydrolysis achieve the displacement of the Hollyday crossing point: in this way the portion of heteroduplex in both double helices.

8) Isomerization: to easily visualize it, imagine that we rotate the two segments of one of the DNA c.d. 180o with respect to the cross-linking point, to generate a flat structure that is isomeric from the previous one ("X structure").

9) Resolution of this structure: this step is catalyzed by the RuvC protein, which cuts and splices two of the chains cross-linked at the Hollyday junction. The result of the resolution may vary depending on whether the chains that were not previously involved in the cross-linking are cut and spliced, or that they are again involved in this second cutting and sealing operation:

a) If the cuts and splices affect the DNA chains that were not previously involved in the cross-linking, the result will be two reciprocal recombinant molecules, where each of the 4 chains are recombinant (there has been an exchange of markers between donor and recipient)

b) If the cuts and splices affect the same chains that had already participated in the first cross-linking, the result will consist of two double helices that present only two portions of heteroduplex DNA.

8 0
4 years ago
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