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2 years ago

Which equation demonstrates the additive identity property?

Mathematics

1 answer:

Alik [6]2 years ago

7 0

Answer:

The second one

Step-by-step explanation:

Additive identity is adding 0 to a number

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Q4 Ali has three pieces of ropes with lengths 140 cm, 168 cm and 210 cm. He wishes to cut all of the pieces of ropes into smalle

Inga [223]

140cm of cousrse i know everything

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3 years ago

If a is an odd integer and b is an even integer, which of the following makes an odd integer?

Serga [27]

9514 1404 393

Answer:

D.) a+2b

Step-by-step explanation:

The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...

A) 3(0) = 0 . . . even

B) 1 +3 = 4 . . . even

C) 2(1+0) = 2 . . . even

D) 1 +2(0) = 1 . . . odd

_____

<em>Additional comment</em>

These rules apply to even/odd:

odd × odd = odd
odd × even = even
even × even = even
odd + odd = even
odd + even = odd
even + even = even

Then A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.

7 0

2 years ago

EXPLAIN

zvonat [6]

Answer:

50,000? This is my answer sorry if wrong

Step-by-step explanation:

4 0

2 years ago

Which graph represents 9(x - 5) = -15y

MAVERICK [17]

Answer:

(0,3) and (5,0)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?

photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

$D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6$

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

$T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326$

What is the probability that they are both queens?

$P = \frac{D}{T} = \frac{6}{1326} = 0.0045$

0.45% probability that they are both queens.

4 0

3 years ago