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2 years ago

10

Which equation demonstrates the additive identity property?

1 answer:

Alik [6]2 years ago

7 0

Answer:

The second one

Step-by-step explanation:

Additive identity is adding 0 to a number

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I need help I’m not sure

Daniel [21]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-6}~,~\stackrel{y_2}{-6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-6+3}{2}~~,~~\cfrac{-6+5}{2} \right)\implies \left(\cfrac{-3}{2}~~,~~\cfrac{-1}{2} \right)\implies \left( -1\frac{1}{2}~,~-\frac{1}{2} \right)$

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3 years ago

Help here ASAP you dont have to write a long one just a short one is fine

pychu [463]

Answer:

Commutative property and associative properties are mixed up.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Triangle ABC has a perimeter 22cm AB = 8cm BC =8cm By calculation, deduce whether triangle ABC is a right angle triangle. NEED A

Likurg_2 [28]

Answer:

No ABC is not a triangle

Step-by-step explanation:

Perimeter = 22 cm

AB = 8 cm ; BC = 8 cm

AC = 22 - ( 8 + 8 ) = 6 cm

But all those sides doesn't follow Pythagorean Theorem(AB^2 + BC^2 = AC^2) ....because 8^2 + 8^2 isn't equal to 6^2 ......

Had it followed the theorem , it could have been a right angle triangle...

6 0

3 years ago

Jeff uses 3 fifth-size strips to mode 3/5. He wants to use tenth-size strips to model an equivalent fraction. How many tenth-siz

galben [10]

Wouldn't it just be 6 tenth sized for 6/10

4 0

3 years ago

Lin counts 5 bacteria under a microscope. She counts them again each day for four days, and finds that the number of bacteria do

Liula [17]

Answer:

The population of bacteria can be expressed as a function of number of days.

Population = $5*2^{n-1}$ where n is the number of days since the beginning.

Step-by-step explanation:

Number of bacteria on the first day= $5 * 2^{0} = 5$

Number of bacteria on the second day = $5 * 2^{1} = 10$

Number of bacteria on the third day = $5*2^{2} = 20$

Number of bacteria on the fourth day = $5*2^{3} = 40$

As we can see , the number of bacteria on any given day is a function of the number of days n.

This expression can be expressed generally as $5*2^{n-1}$ where n is the number of days since the beginning.

6 0

3 years ago