the oscillation of rod oa about o is defined by the relation θ= (3/pi)*(sin*pi*t), where theta and t are expressed in radians an
d seconds, respectively. collar B slides along the rod so that its distance from O is r = 6(1-e^-2t) where r and t are expressed in inches and seconds. When t =1s determine (a) the velocity of the collar, (b) the acceleration of the collar (c) the acceleration of the collar relative to the rod
1 answer:
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Answer:
Logarithmic decrement is equal to 0.182
Explanation:
given,
amplitude decay = 9 dB
number of cycles = 12 cycles
mass of the system = 7 kg
spring stiffness = 3000 N/m
logarithmic decrement = ?
now,
logarithmic decreament =
=
=ln (1.2)
= 0.182
Hence, Logarithmic decrement is equal to 0.182
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