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sweet-ann [11.9K]
3 years ago
8

the oscillation of rod oa about o is defined by the relation θ= (3/pi)*(sin*pi*t), where theta and t are expressed in radians an

d seconds, respectively. collar B slides along the rod so that its distance from O is r = 6(1-e^-2t) where r and t are expressed in inches and seconds. When t =1s determine (a) the velocity of the collar, (b) the acceleration of the collar (c) the acceleration of the collar relative to the rod

Engineering
1 answer:
Mashcka [7]3 years ago
4 0

Answer:

(a) The velocity of the collar = 1.624er-15.54eo in/s

(b) the acceleration of the collar=-49.94er-9.74eo in/s²

(c)the acceleration of collative rod =-3.284er in/s²

Explanation:

Check attachment for calculation

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Design a circuit that will output HIGH when the input is a prime number larger than 2 and smaller than 16. The input should be a
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5 0
3 years ago
A 300 mm long steel bar with a square cross section (25 mm per edge) is pulled in tension with a load of 84998 N , and experienc
german

Answer:

Elastic Modulus = 227 GPa

Explanation:

Given,

Load = 84998 N

Length of bar = 300 mm = 0.3 m

Elongation = 0.18 mm = 0.00018 m

Cross sectional Area of the bar = (25mm × 25mm) = 0.025 × 0.025 = 0.000625 m²

From Hooke's law, the stress experienced by a material is proportional to the strain experienced by the same body, as long as the elastic limit isn't exceeded.

Stress ∝ strain

The coefficient of proportionality is the elastic modulus, E.

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Strain = (ΔL/L) = 0.00018 ÷ 0.3 = 0.0006

E = (Stress/Strain)

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Hope this Helps!!!

4 0
3 years ago
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