Question

Find the general solution of the equationa) Tan A = 1/√3​

Answer 1

Given :

$tan \ A = \dfrac{1}{\sqrt{3}}$

To Find :

The general solution of the given equation.

Solution :

We know, $tan\ 30^o = \dfrac{1}{\sqrt{3}}$

Comparing it with given equation, we get :

$A = \dfrac{\pi}{6}$

General solution is given by :

$A = n\pi + \dfrac{\pi}{6}$ where n ∈ Z ( integers )

Hence, this is the required solution.