The total amount of the resulting mixture can be calculated by adding up the volume of the given substances assuming that volume addition is applicable given the properties of the fluids used.
That is,
T = 6 quarts + 10 quarts = 16 quarts
The total volume of the resulting mixture is 16.
Then, we do the component (antifreeze) balance by adding up the resulting antifreeze from the substances to the total. We let x be the percentage of antifreeze in the final mixture.
6(0.52) + 10(0.32) = 16(x)
The value of x from the equation is 0.395.
Therefore, the answer to this item is 39.5%.
The zeroes are
0, -5, 3 + i (and its conjugate)
The factors are
x (x + 5) (x - (3 + i)) (x - (3 - i))
Expanding...
(x² + 5x)((x - 3) - i) ((x - 3) + i)
(x² + 5x)((x - 3)² - i²)
(x² + 5x)(x² - 6x + 9 - (-1))
(x² + 5x)(x² - 6x + 10)
x⁴ - 6x³ + 10x² + 5x³ - 30x² + 50x
x⁴ - x³ - 20x² + 50x
7/12n is the answer to your question
Answer:229.1
Step-by-step explanation: to much work I thought to hard that’s the answer your welcome buddy
