Answer:
The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>
Step-by-step explanation:
Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.
We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

Since, given the difference of the squares of the numbers is 5 that is 
And the product of the numbers is 6 that is 
Using identity, we have,

Substitute, we have,

Simplify, we have,


Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169
Using the distributive property the product is -12x-20. To distribute you take the numbers and or variables outside of the paranthesis and multiply it by each one in the parenthesis such that 4x is multiplied by -3x getting -12x and multiplying 4x by -5 and the product is -20x and all together the answer is -12x-20
Answer: 47/25, The simplest form is 47/25, mixed number version is 1 22/25
.
Step-by-step explanation: Please mark as brainliest!
You plug -x+16 in for y in x+4y=37 to get x after you multiply x+4y=37 by -1.
-x-4(-x+16)=-37
-x+4x-64=-37
3x-64=-37
3x=27
x=9
Then you plug 9 into either equation to get y.
y=-x+16
y=-(9)+16
y=7
x=9 and y=7
Factoring may be the easiest one