The probability that a truck drives between 150 and 156 miles in a day is 0.0247. Using the standard normal distribution table, the required probability is calculated.
<h3>How to calculate the probability distribution?</h3>
The formula for calculating the probability distribution for a random variable X, Z-score is calculated. I.e.,
Z = (X - μ)/σ
Where X - random variable; μ - mean; σ - standard deviation;
Then the probability is calculated by P(Z < x), using the values from the distribution table.
<h3>Calculation:</h3>
The given data has the mean μ = 120 and the standard deviation σ = 18
Z- score for X =150:
Z = (150 - 120)/18
= 1.67
Z - score for X = 156:
Z = (156 - 120)/18
= 2
So, the probability distribution over these scores is
P(150 < X < 156) = P(1.67 < Z < 2)
⇒ P(Z < 2) - P(Z < 1.67)
From the standard distribution table,
P(Z < 2) = 0.97725 and P(Z < 1.67) = 0.95254
On substituting,
P(150 < X < 156) = 0.97725 - 0.95254 = 0.02471
Rounding off to four decimal places,
P(150 < X < 156) = 0.0247
Thus, the required probability is 0.0247.
Learn more about standard normal distribution here:
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