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Mashcka [7]
2 years ago
14

Quadratic Equations: Write x^2 - 3x + 2 = 0 in standard form and determine a, b, and c

Mathematics
2 answers:
Anna35 [415]2 years ago
7 0
The answers your looking for are: A.1 B.3 C.2 and x=2,1 hope this helped have a nice day :)
anyanavicka [17]2 years ago
5 0
A=1
b=-3
c=2
x=2,1

Hope this helped :-)
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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
2 years ago
0.5y-2 2/5=1/2y+2.4<br><br>Help :l
lesya [120]

Answer:

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4 0
3 years ago
How to solve 19= -37 + 8x
lions [1.4K]

Answer:

19 = -37 + 8x

-8x= -37 -19

-8x = -56

x= 7

4 0
2 years ago
All the pupils at a primary school come from one of three villages: Elmswell, Haughley or Woolpit. 1/4 of the pupils come from E
Jlenok [28]

Answer:

<em>680</em>

Step-by-step explanation:

Given that:

All the pupils at a primary school come from one of three villages: Elmswell, Haughley or Woolpit.

\frac{1}{4} of the pupils come from Elmswell

\frac{3}{5} of the pupils come from Haughley

102 pupils come from Woolpit.

To find:

Total number of pupils in the school.

Solution:

Let total number of pupils = 100x

So, number of pupils that come from Elmswell = \frac{1}{4} of 100x

OR

\dfrac{1}{4} \times 100x\\\Rightarrow 25x

And, number of pupils that come from Haughley= \frac{3}{5} of 100x

OR

\dfrac{3}{5} \times 100x\\\Rightarrow 60x

Number of pupils that come from Woolpit = 100x - 25x - 60x \Rightarrow 15x

As per given statement:

15x = 102\\\Rightarrow x =6.8

Number of pupils from Elmswell = 25x = 25 \times 6.8 = 170

Number of pupils from Haughley = 60x = 60 \times 6.8 = 408

Total number of pupils at the school = 100x \Rightarrow 100 \times 6.8=680

7 0
2 years ago
Plz help :( what is 10,000,000(20)^10 !?
Sergio [31]

Answer: 102,400,000,000,000,000,000

Step-by-step explanation:

First do 20^10 = 10,240,000,000,000.  

Then, multiply 10,240,000,000,000 * 10,000,000 to get 102,400,000,000,000,000,000.

<em>Hope it helps <3</em>

7 0
3 years ago
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