Question

Find the missing side of the right triangle

Answer 1

Answer:

1

Step-by-step explanation:

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=3,\ leg=x,\ hypotenuse=\sqrt{10}$

Substitute:

$3^2+x^2=(\sqrt{10})^2$

$9+x^2=10$             subtract 9 from both sides

$9-9+x^2=10-9$

$x^2=1\to x=\sqrt1\\\\x=1$