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3 years ago

Find the missing side of the right triangle

Mathematics

1 answer:

o-na [289]3 years ago

7 0

Answer:

Step-by-step explanation:

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=3,\ leg=x,\ hypotenuse=\sqrt{10}$

Substitute:

$3^2+x^2=(\sqrt{10})^2$

$9+x^2=10$ <em>subtract 9 from both sides</em>

$9-9+x^2=10-9$

$x^2=1\to x=\sqrt1\\\\x=1$

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masha68 [24]

Answer:

A) (x + 2)

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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2 years ago

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2 years ago

F(x)=12x2-4x-8. G(x)=11x-6

AlekseyPX

Answer: Second option.

Step-by-step explanation:

Given the functions f(x) and g(x):

$f(x)=12x^2-4x-8\\\\g(x)=11x-6$

You need to divide them in order to find $(\frac{f}{g})(x)$ asked in the exercise. Then:

$(\frac{f}{g})(x) =\frac{12x^2-4x-8}{11x-6}$

Now, it is important to remember that, by definition, the division by zero is not defined. Therefore, the denominator of the function cannot be zero.

Let's find the value of "x" for which the denominator of the function would be zero:

1. You need to make the denominator equal to zero:

$11x-6=0$

2. Finally, you must solve for "x":

$11x=6\\\\x=\frac{6}{11}$

Therefore, as you can see, the answer is:

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3 years ago