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Daniel [21]
3 years ago
8

A line is parallel to the line y = 2/3x+1 and passes through the point (4,-1) Determine the Slope on the line

Mathematics
1 answer:
Llana [10]3 years ago
8 0

M = Slope

(4,-1) = Vertical Intercept

Slope can be found by puting y/x which is 2/3 meaning the slope would be 0.66, but x+1 would change the vertices intercept. Keep in mind my math is NOT perfect as I am also still learning slope and linear relationships.

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Multiply the following rational expressions and simplify the result
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Answer:

Step-by-step explanation:

We have to solve the given expression,

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y} = \frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{7y^2+10y+7y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{y(7y+10)+1(7y+10)}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{(y+1)(7y+10)}{14y(y+2)}

                                   = \frac{-3y(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14y(y+2)}

                                   = \frac{-3(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14(y+2)}

                                   = \frac{3(3-11y-y^3)(y+1)}{(10-7y)(14(y+2)}

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