Question

Ammonium carbonate decomposes upon heating according to the following balanced equation:

Answer 1

Answer : The total volume of gas produced are, 11.5 L

Explanation :

First we have to calculate the moles of ammonium carbonate.

$\text{Moles of }(NH_4)_2CO_3=\frac{\text{Mass of }(NH_4)_2CO_3}{\text{Molar mass of }(NH_4)_2CO_3}$

Molar mass of $(NH_4)_2CO_3$ = 96.094 g/mol

$\text{Moles of }(NH_4)_2CO_3=\frac{11.9g}{96.094g/mol}$

$\text{Moles of }(NH_4)_2CO_3=0.124mol$

Now we have to calculate the moles of total gas.

The given balanced chemical reaction is:

$(NH_4)_2CO_3(s)\rightarrow 2NH_3(g)+CO_2(g)+H_2O(g)$

From the balanced chemical reaction we conclude that,

As, 1 mole of $(NH_4)_2CO_3$ react to give 4 mole of gas

So, 0.124 mole of $(NH_4)_2CO_3$ react to give $0.124\times 4=0.496$ mole of gas

Now we have to calculate the volume of gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of gas = 1.05 atm

V = Volume of gas = ?

n = number of moles = 0.496 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas = $24.0^oC=273+24.0=297.0K$

Putting values in above equation, we get:

$1.05atm\times V=0.496mole\times (0.0821L.atm/mol.K)\times 297.0K$

$V=11.5L$

Thus, the total volume of gas produced are, 11.5 L