We can solve this problem using the long hand solution, wherein we 1 by 1 analyze the different equilibrium reactions or by simply using the Henderson Hasselbach equation. The equation is
pH = -log(pKa) + log (salt/acid)
since the acid and the salt have the same concentration, the log (salt/acid) term is equal to zero.
thus
pH = -log(1.73*10-5)
pH = 4.76
please be careful with the negative sign
Complete Question
The complete question is shown on the first uploaded image
Answer:
The pressure is
Explanation:
From the question we are told that
The mass of the carbon monoxide is
The temperature at which takes place
The volume of the sealed vessel is
Generally the ideal gas law is mathematically represented as
Where R is the gas constant with value
n is the number of moles of carbon monoxide which is mathematically evaluated as
where is the molar mass of carbon monoxide which is a constant with value
So
Now Making P the subject we have
A, because a synthesis reaction is A+B—> AB
B is a decomposition AB—> A+B (opposite of synthesis)
C is acids and base acid 1 + base 1 —> acid 2 + base 2
D is double displacement AB+CD —> AD+CB
When two negatively charged particles interact with one another, the particles repel with each other. Opposite charges attract while like charges repel. A negatively charged object will exert a repulsive force upon a second negatively charged object. Hope this helps.
First, find how many copper atoms make up the ball:
<span>moles of atoms = (46.6 g) / (63.5 g per mol of atoms) = 0.73385 mol </span>
<span># of atoms = (0.73385 mol) (6.02 × 10^23 atoms per mol) = 4.4178 × 10^23 atoms </span>
<span>There is normally one electron for every proton in copper. This means there are normally 29 electrons per atom: </span>
<span>normal # electrons = (4.4178 × 10^23 atoms) (29 electrons per atom) = 1.2811 × 10^25 electrons </span>
<span>Currently, the charge in the ball is 2.5 µC, which means -2.5 µC worth of electrons have been removed. </span>
<span># removed electrons = (-2.5 µC) / (1.602 × 10^-13 µC per electron) = 1.5604 × 10^13 electrons removed </span>
<span># removed electrons / normal # electrons = </span>
<span>(1.5604 × 10^13 electrons removed) / (1.2811 × 10^25 electrons) = 1.22 × 10^-12 </span>
<span>That's 1 / 1.22 × 10^12 </span>