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Vlada [557]
2 years ago
9

Simplify. 8(12 - p) 20 - (8+p) 96 - 8p 96 - p 96p

Mathematics
1 answer:
Romashka [77]2 years ago
6 0

<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>C</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>Hope </em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em> </em><em>.</em><em>.</em>

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12.Divide. (x^2+2x+1/x^2-8x+16)/(x+1/x^2-16
lina2011 [118]
For this case we have the following expression:
 (x ^ 2 + 2x + 1 / x ^ 2-8x + 16) / (x + 1 / x ^ 2-16)
 Rewriting we have:
 (((x + 1) (x + 1)) / ((x-4) (x-4))) / (x + 1 / ((x + 4) (x-4)))
 Then, we cancel similar terms:
 ((x + 1) / (x-4)) / (1 / (x + 4))
 Rewriting:
 ((x + 1) (x + 4)) / (x-4)
 Answer:
 
((x + 1) (x + 4)) / (x-4)
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3 years ago
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kifflom [539]
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kobusy [5.1K]
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A company uses a combination of three components- A, B and C to create three different drone designs. The first design Glider us
FrozenT [24]

Answer:

Consider the following calculations

Step-by-step explanation:

Since 1 Blimp uses 2 components of B and C each

=> choosing 2 components of B(remaining after using in other prototypes) for 1st model= 22C2

choosing 2 components of B(remaining after using in other prototypes) for 2nd model= 21C2

choosing 2 components of B(remaining after using in other prototypes) for 3rd model= 20C2

choosing 2 components of B(remaining after using in other prototypes) for 4th model= 19C2

choosing 2 components of B(remaining after using in other prototypes) for 5th model= 18C2

and choosing 2 components of C(remaining after using in other prototypes) = 24C2

Similarly for C

P(5 prototypes of Blimp created)=[(22C2 / 25C2 )*(24C2 / 25C2 )] + [(21C2 / 25C2 )*(23C2 / 25C2 )]+[(20C2 / 25C2 )*(22C2 / 25C2 )]+[(19C2 / 25C2 )*(21C2 / 25C2 )]+[(18C2 / 25C2 )*(20C2 / 25C2 )]

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723 divided bye 34 in partial
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The answer is 0.04702628
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