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jeka94
3 years ago
10

The table below shows the total cost (TC) and marginal cost (MC) for Choco Lovers, a monopolistic firm producing different quant

ities
of chocolate gift boxes. Fill in the blanks in the table.

Mathematics
1 answer:
goblinko [34]3 years ago
4 0

Answer:

  Spreadsheet values

  • B3 = $15 (shown)
  • C4 = $420 (shown)
  • D6 = $272.5
  • E4 = $6
  • F2 = $16
  • F6 = $5

  Other values

  • profit maximizing Q: 35
  • profit maximizing P: $13
  • maximum profit: $227.5

Step-by-step explanation:

Labeling the columns of the spreadsheet A--F, and the rows 1--7, we want to find the values as follows.

a) The relationship between quantity, price, and revenue is ...

  total revenue = quantity × price

  price = (total revenue)/quantity

Then ...

  • B3 = 375/25 = 15 (as shown)
  • C4 = 30×14 = 420 (as shown)

__

b) The relationship between total cost and marginal cost is ...

  mc2 = (tc2 -tc1)/(q2 -q1)

  tc2 = (mc2)(q2 -q1) +tc1

Then ...

  • D6 = 9(40 -35) +227.5 = 272.5
  • E4 = (192.5 -162.5)/(30 -25) = 6

__

c) Marginal revenue is figured the same way as marginal cost.

  mr2 = (r2 -r1)/(q2 -q1)

Then ...

  • F2 = (320 -0)/(20 -0) = 16
  • F6 = (480 -455)/(40 -35) = 5

__

d) The quantity maximizing profit will be the quantity such that marginal revenue is equal to marginal cost. That is, marginal profit is zero. That quantity  is 35, where both marginal cost and marginal revenue are 7.

__

e) The price at a quantity of 35 is 13. This value is read from the given table.

__

f) The maximum profit is the difference between revenue and cost at the profit-maximizing quantity:

  maximum profit = 455 -227.5 = 227.5

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A health statistics agency in a certain country tracks the number of adults who have health insurance. Suppose according to the
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Answer:

a) There is a 15.3% probability that a randomly selected person in this country is 65 or older.

b) Given that a person in this country is uninsured, there is a 2.2% probability that the person is 65 or older.

Step-by-step explanation:

We have these following percentages:

5.3% of those under the age of 18, 12.6% of those ages 18–64, and 1.3% of those 65 and older do not have health insurance.

22.6% of people in the county are under age 18, and 62.1% are ages 18–64.

(a) What is the probability that a randomly selected person in this country is 65 or older?

22.6% are under 18

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The rest are above 65

So

100% - (22.6% + 62.10%) = 15.3%

There is a 15.3% probability that a randomly selected person in this country is 65 or older.

b) Given that a person in this country is uninsured, what is the probability that the person is 65 or older?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So, what is the probability that a person is 65 and older, given that the person is uninsured.

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P(A/B) is the probability is uninsured, given that that person is 65 and older. So P(A/B) = 0.013

P(A) is the probability that a person is uninsured. That is the sum of 5.3% of 22.6%, 12.6% of 62.1% and 1.3% of 15.3%. So:

P(A) = 0.053*(0.226) + 0.126*(0.621) + 0.013*(0.153) = 0.0922

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.153*0.013}{0.0922} = 0.022

Given that a person in this country is uninsured, there is a 2.2% probability that the person is 65 or older.

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Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

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\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

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y = 22°/2 = 11°

The variable, y = 11°

8 0
2 years ago
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