Using squares of integers numbers, it is found that the solution of the equation is located between the integers x = 1 and x = 2.
The equation given is:
The solution of the equation given is:
The squares of the integers numbers until the square root of 3 are:
Since 
, the square root of 3, which is the solution to the equation, is located between the integers x = 1 and x = 2.
A similar problem is given at brainly.com/question/3729492
Step-by-step explanation:
Actually, 40 is divisible by 7. Any number is divisible by 7. However, 7 does not go into forty evenly. Your quotient would have a remainder since 7 cannot go into 40 an even number of times.
7 goes into 40 5 times evenly (7x5=35) 40-35 is five, so 40 divided by 7 is 5 (remainder 5)
~theLocoCoco
Yes, they can be added and simplified further. 2√3 + 5√3 = 7√3 .
Take √3 as common factor:
2√3 + 5√3
(2 + 5)√3
7√3
The two irrational numbers sums to form another irrational number 7√3 . In decimals that is 12.12435...
