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Sergio039 [100]
3 years ago
15

How far apart are two conducting plates that have an electric field strength of 4.5 × 103V/m between them, if their potential

difference is 12.5 kV?
Physics
1 answer:
nalin [4]3 years ago
8 0

Answer:

Explanation:

Given

Electric Field Strength E=4.5\times 10^{3}\ V/m

Potential Difference between Plates is given by V=12.5\ kV

In conducting plates a Potential difference exist between two plate which accelerate the charge when put between the conducting plates

The potential difference is given by

\Delta V=Ed

where E=Electric Field strength

d=distance between Plates

d=\frac{\Delta V}{E}

d=\frac{12.5\times 10^3}{4.5\times 10^{3}}

d=2.78\ m

     

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The formula agNo3 represents q compound made of which atoms?
Alenkinab [10]

Explanation :

AgNO_3 is silver nitrate. In this compound, one atom of silver, one atom of nitrogen and three atoms of oxygen are present.

We know from the concept of mole concept that the number of molecules, atoms or ions present in a substance is known as one mole.

The number of particles in one mole of a substance is defined as Avogadro's number.

So, we can say that silver, nitrogen and oxygen are present in AgNO_3.

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3 years ago
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Ratatouille is my momCan you lend me 700 because I used my toaster as a bath heater and now my legs are gone plz I need money for bandages
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16. Two capacitors have an equivalent
Gennadij [26K]

Answer:

C1 + C2 = 30     parallel connection

C1 * C2 / (C1 + C2) = 7.2  series connection

C1 * C2 = 7.2 * (C1 + C2) = 216

C2 + 216 / C2 = 30    using first equation

C2^2 + 216 = 30 C2

C2^2 - 30 C2 + 216 = 0

C2 = 12 or 18    solving the quadratic

Then C1 = 18 or 12

5 0
3 years ago
Hello! Please I need help on 1. (C) I dont know the formula to get the Total height using Mechanical Energy
inna [77]

Answer:

4.00m

Explanation:

at that instant where it is dropped all the mechanical energy is gpe which is 71.9

and the formula for gpe = mass (1.80) * height * gravitational field strength (i'm using 10 m/s2)

height of football stadium

= 71.9/[(1.80)(10)]

= 71.9/18.0

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4 0
4 years ago
A hydraulic press has one piston of diameter 4.0 cm and the other piston of diameter 8.0 cm. What force must be applied to the s
yan [13]

Answer:

The  force is F_1  = 400.8 \  N

Explanation:

From the question we are told that

   The first  diameter is  d_1 =  4.0 \ cm =  0.04 \ m

   The second diameter is  d_2  =  8.0 \ cm  = 0.08 \  m

   

Generally the first area is  

         A_1  =  \pi  * \frac{d^2_1 }{4}

=>      A_1  = 3.142  * \frac{0.04^2}{4}

=>       A_1  =  0.00126 \ m^2

The  second area is  

     A_2 =  \pi  * \frac{d^2_2 }{4}

     A_2  = 3.142  * \frac{0.08^2}{4}

     A_2  =  0.00503 \ m^2

For a hydraulic press the pressure at both end must be equal .

Generally  pressure is mathematically represented as

    P =  \frac{F}{A}

=>  

   \frac{F_1}{A_1 }  =  \frac{F_2}{A_2 }

=>   F_1  =  \frac{1600}{0.00503}  *  0.00126

=>    F_1  = 400.8 \  N

8 0
3 years ago
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