Answer:
the awnser is A becuse the hair help.
Answer:
65.625 m/s
Explanation:
![F=20\times 10^9 Hz](https://tex.z-dn.net/?f=F%3D20%5Ctimes%2010%5E9%20Hz)
![\Delta F=F_r-F_t=4750 Hz](https://tex.z-dn.net/?f=%5CDelta%20F%3DF_r-F_t%3D4750%20Hz)
c = Speed of light = 3×10⁸ m/s
Relative speed
![v=\frac{\Delta F}{2F}\times c\\\Rightarrow v=\frac{4750}{2\times 20\times 10^9}\times 3\times 10^8\\\Rightarrow v=35.625\ m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B%5CDelta%20F%7D%7B2F%7D%5Ctimes%20c%5C%5C%5CRightarrow%20v%3D%5Cfrac%7B4750%7D%7B2%5Ctimes%2020%5Ctimes%2010%5E9%7D%5Ctimes%203%5Ctimes%2010%5E8%5C%5C%5CRightarrow%20v%3D35.625%5C%20m%2Fs)
Relative speed = 35.625 m/s
Velocity of speeder = Velocity of police car + Relative speed
⇒Velocity of speeder = 30 + 35.625 = 65.625 m/s
∴ Velocity of speeder is 65.625 m/s
Answer: Heat transfers through brick walls and glass through conduction. In conduction heat is transferred by vibration of molecules. most energetic molecules vibrate and pass on the energy to less energetic molecules. Then they vibrate and further pass on the energy. In this way heat is transferred out of the home. Heat also transfers through the leakage of warm air from doors and windows. This occurs through convection. In convection energy is transferred through bulk movement of liquid and air molecules. Heat also transfers from insulation. in insulation there is no material in between the layers. So heat transfer through insulation occurs through radiations that occurs by X-Rays, Ultravoilet rays etc.
Answer:
v2 = 27.3m/s
Explanation:
Assuming forward as positive.
Mass = m1 = 64kg
Let v be the common velocity of the student and the skateboard.
mass of skateboard = m2 = 5.94kg
v = 1.4m/s
Since the skateboard and the student are initially moving together at the same velocity their momentum together is
(m1 + m2)v
Let the final velocity of the student be v1 and the final velocity of the skateboard be v2
v1 = – 1.0m/s (falls backwards that's why the velocity is negative since we are assuming forward as positive)
Then from conservation of momentum, momentum before is equal to momentum after.
(m1 + m2)v = m1v1 + m2v2
m2v2= (m1 + m2)v – m1v1
v2 = ( (m1 + m2)v – m1v1)/m2
v2 = ( (64 + 5.94)×1.4 – 64×(-1.0))/5.94
v2 = ( (64 + 5.94)×1.4 + 64×1.0)/5.94
v2 = 27.3m/s