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3 years ago

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This is a model of a Neon atom. How likely is it that this atom would want to bond with another atom? Neon atom Question 5 optio

ns:
A.This atom is very likely to bond with another atom.
B. This atom is only slightly likely to bond with another atom
C.This atom is not likely at all to bond with another atom.

1 answer:

juin [17]3 years ago

3 0

If this is just a normal model of a Neon atom in which it has 2 electrons in the first shell and 8 in the second, then this atom is not likely at all to bond with another atom because it has 8 electrons in its outermost or valence shell. Because 8 is 8, Neon doesn't need to combine with another element.

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Amanda [17]

A) $+1.67 rad/s^2$

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$\alpha = \frac{\omega_f - \omega_i}{\Delta t}$

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$\omega_f = 4.00 rad/s$ is the final angular velocity (anticlockwise, so with a positive sign)

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B) 3.6 s

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$\alpha = \frac{\omega_f - \omega_i}{\Delta t}$

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C) 2.4 s

The time interval during which the angular velocity is idecreasing is the time interval between the initial instant $t_1=0$ when $\omega_i=-4.00 rad/s$ ) and the time corresponding to the instant in which the velovity becomes positive $t_2$ , when $\omega_f = 0 rad/s$ . We can find this time interval by using

$\alpha = \frac{\omega_f - \omega_i}{\Delta t}$

And solving for $\Delta t$ we find

$\Delta t = \frac{\omega_f - \omega_i}{\alpha}=\frac{0-(-4.00 rad/s)}{+1.67 rad/s^2}=2.4 s$

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$\omega_f^2 - \omega_i^2 = 2 \alpha \theta$

where we have

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$\omega_f = 4.00 rad/s$ is the final angular velocity

$\alpha=+1.67 rad/s^2$ is the angular acceleration

Solving for $\theta$ ,

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