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Ivenika [448]
2 years ago
5

When drawing up liquid into a micropipette, put the tip in the liquid at a Choose... degree angle, push the plunger to the Choos

e... point of resistance, and then Choose... the plunger. When dispensing that liquid from the micropipette, hold the micropipette at a Choose... degree angle in the desired container and push the plunger to the Choose... point of resistance. Choose... the plunger until dispensing is done.
Physics
1 answer:
tangare [24]2 years ago
3 0

Answer:

Explanation:

This question seeks to test the knowledge of operating a micropipette.

When trying to draw a liquid from a container using a micropipette (tip), the micropipette should be <u>held vertically straight at an angle of 90 degrees</u> with the plunger pushed to the <u>first resistance</u> and then released.

When trying to dispense the drawn liquid into another container, the micropipette is <u>held vertically straight at the same 90 degrees</u> but the plunger is pushed to the <u>second/last</u> point of resistance. <u>You keep pressing</u> the plunger at the same degree and resistance until dispensing is done.

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You wish to produce an emf of 41.0 mV using an inductor whose inductance is 13.0 H. You start with a current of 1.50 mA through
Molodets [167]

Answer:

The current through the inductor at the end of 2.60s is 9.7 mA.

Explanation:

Given;

emf of the inductor, V = 41.0 mV

inductance of the inductor, L = 13 H

initial current in the inductor, I₀ = 1.5 mA

change in time, Δt = 2.6 s

The emf of the inductor is given by;

V = L\frac{di}{dt} \\\\V = \frac{L(I_1-I_o)}{dt} \\\\L(I_1-I_o) = V*dt\\\\I_1-I_o = \frac{V*dt}{L}\\\\I_1 =  \frac{V*dt}{L} + I_o\\\\I_1 = \frac{41*10^{-3}*2.6}{13} +1.5*10^{-3}\\\\I_1 = 8.2*10^{-3} + 1.5*10^{-3}\\\\I_1 = 9.7 *10^{-3} \ A\\\\ I_1 = 9.7 \ mA

Therefore, the current through the inductor at the end of 2.60 s is 9.7 mA.

6 0
3 years ago
during the course of songraphic exam, you notice lateral splaying of echoes in the far field. what can you do to improve the ima
horrorfan [7]

Answer:

lateral splaying of echoes in the far field can be improved by Increasing the maximum number of transmit focal zones and optimize their location.

8 0
2 years ago
An airplane flies eastward and always accelerates at a constant rate. At one position along its path it has a velocity of 34.3 m
Tomtit [17]

Explanation:

We'll need two equations.

v² = v₀² + 2a(x - x₀)

where v is the final velocity, v₀ is the initial velocity, a is the acceleration, x is the final position, and x₀ is the initial position.

x = x₀ + ½ (v + v₀)t

where t is time.

Given:

v = 47.5 m/s

v₀ = 34.3 m/s

x - x₀ = 40100 m

Find: a and t

(47.5)² = (34.3)² + 2a(40100)

a = 0.0135 m/s²

40100 = ½ (47.5 + 34.3)t

t = 980 s

7 0
3 years ago
Explain the role of energy in changes <br> of state.
slava [35]
A liquid requires enthalpy of vaporization to transform into vapor or gas at its boiling point.  Here the element absorbs heat from surroundings or heat source.

This energy is used in breaking the forces of attraction among the atoms and molecules of the element. The molecules get separated to higher distances. The energy is converted in to the kinetic energy of the molecules in gaseous form and into the internal energy in terms of the temperature of the gas.


3 0
3 years ago
Question is attatched!
lina2011 [118]
All it does is lets him pull in a more convenient direction to raise the load. It has no effect on the required force.
4 0
3 years ago
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