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Kobotan [32]
2 years ago
8

Assume this is an acceleration graph, where the X axis represents time in seconds and the Y axis represent velocity in m/s. Whic

h statement BEST describes the acceleration represented by the graph?
A)There is no acceleration.
B) Acceleration is positive.
C) Acceleration is positive and constant.
D) Acceleration is positive and increasing.

Physics
2 answers:
lakkis [162]2 years ago
6 0

Answer:

D

Explanation:

Vilka [71]2 years ago
3 0

Answer:

D) Acceleration is positive and increasing.

Explanation:

Acceleration is defined as the rate of change of velocity per unit time; in formulas:

a=\frac{\Delta v}{\Delta t}

where \Delta v is the variation of velocity and \Delta t is the variation in time.

The graph shows the velocity vs the time of a moving object. We can see that \Delta v is the increment on the y-axis, while \Delta t is the increment on the x axis: therefore, the ratio \frac{\Delta v}{\Delta t} is the slope of the curve. In fact, in a velocity-time graph, the slope of the curve corresponds to the acceleration of the object.

In this particular graph, we see that the slope of the curve continues to increase: therefore, the acceleration is positive (because the slope is positive, since the velocity is increasing) and increasing (because the slope is increasing).

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Despite a vigorous training schedule and careful meal planning, Anthony “hit the wall” at mile 12 of his half-marathon and he ha
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Condition of fatigue caused by depletion of glycogen

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5 0
3 years ago
A thin, metallic spherical shell of radius 0.227 m has a total charge of 6.03 × 10 − 6 C placed on it.
KATRIN_1 [288]

Answer:

Explanation:

Given

radius r=0.227 m

Charge on surface Q=6.03\times 10^{-6} C

Point Charge inside sphere q=1.15\times 10^{-6} C

Electric Field at r=0.735 m

Treating Surface charge as Point charge and applying Gauss law

E_{total}A=\frac{q_{enclosed}}{\epsilon _0}

where A=surface area up to distance r

E_{total}=\frac{Q+q}{4\pi r^2}

E_{total}=\frac{6.03\times 10^{-6}+1.15\times 10^{-6}}{4\pi (0.735)^2\times 8.85\times 10^{-12}}

E_{total}=1.194\times 10^{5} N/C

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