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choli [55]
3 years ago
14

A car is travelling with a velocity of 10 m/s and has a mass of 550 kg. The car has energy.

Physics
1 answer:
Elenna [48]3 years ago
3 0

Answer: The car has a kinetic energy (because it's in motion) of:  27500J

Explanation:

Formula: E=\frac{1}{2}mv^2

E=\frac{1}{2}mv^2

E=\frac{1}{2}(550kg)(10m/s)^2

E=\frac{1}{2}(550kg)(100m^2/s^2)

E=\frac{1}{2}(55000J)\\E=27500J

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A professor, with dumbbells in his hands and holding his arms out, is spinning on a turntable with an angular velocity. What hap
Olenka [21]

Answer:

<em>His angular velocity will increase.</em>

Explanation:

According to the conservation of rotational momentum, the initial angular momentum of a system must be equal to the final angular momentum of the system.

The angular momentum of a system = I'ω'

where

I' is the initial rotational inertia

ω' is the initial angular velocity

the rotational inertia = mr'^{2}

where m is the mass of the system

and r' is the initial radius of rotation

Note that the professor does not change his position about the axis of rotation, so we are working relative to the dumbbells.

we can see that with the mass of the dumbbells remaining constant, if we reduce the radius of rotation of the dumbbells to r, the rotational inertia will reduce to I.

From

I'ω' = Iω

since I is now reduced, ω will be greater than ω'

therefore, the angular velocity increases.

5 0
3 years ago
A container with rigid walls is filled with 4.0 mol of air with Cv=2.5R Then the temperature is increased from 17 degrees C to 3
galina1969 [7]

Explanation:

Internal energy = heat + work

U = Q + W

Since there's no change in volume (rigid walls), W = 0.

U = Q

U = n Cᵥ ΔT

U = (4.0 mol) (2.5 × 8.314 J/mol/K) (354 C − 17 C)

U = 28,000 J

3 0
3 years ago
If you were to stand in the exact center of a rotating disc, you would only have what kind of
Dmitriy789 [7]

Answer:

Tangential speed or Rotational speed

3 0
3 years ago
You are given an unknown solid substance of mass 500 g and you want to estimate its specific heat. unfortunately, you don’t have
Julli [10]

Answer:

Option C) 2,090 J/(mol K)

Explanation:

Data:

Volume in the beaker = 429 ml

temperature  = 20° C

Density = 789 kg/m³

Equilibrium reading = 429

volume change = 29 ml

                          = 0.029 L

Energy change = mcΔT

                       U + PΔV

7 0
3 years ago
Objects with masses of 135 kg and a 435 kg are separated by 0.500 m. Find the net gravitational force exerted by these objects o
IrinaVladis [17]

Answer:

The net gravitational force on the mass is 1.27\times 10^{-5}

Explanation:

We have by Newton's law of gravity the force of attraction between masses m_{1},m_{2}

F_{att}=G\frac{m_{1}m_{2}}{r^{2}}

Applying vales we get

Force of attraction between 135 kg mass and 38 kg mass is

F_{1}=6.67\times 10^{-11}\frac{135\times 38}{(0.25)^{2}}\\\\F_{1}=5.47\times 10^{-6}N

Force of attraction between 435 kg mass and 38 kg mass is

F_{2}=6.67\times 10^{-11}\frac{435\times 38}{(0.25)^{2}}\\\\F_{2}=1.76\times 10^{-5}N

Thus the net force on mass 38.0 kg is F_{2}-F_{1}=1.76\times 10^{-5}-5.47\times 10^{-6}\\\\F_{2}-F_{1}=1.27\times 10^{-5}

8 0
3 years ago
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