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choli [55]
3 years ago
14

A car is travelling with a velocity of 10 m/s and has a mass of 550 kg. The car has energy.

Physics
1 answer:
Elenna [48]3 years ago
3 0

Answer: The car has a kinetic energy (because it's in motion) of:  27500J

Explanation:

Formula: E=\frac{1}{2}mv^2

E=\frac{1}{2}mv^2

E=\frac{1}{2}(550kg)(10m/s)^2

E=\frac{1}{2}(550kg)(100m^2/s^2)

E=\frac{1}{2}(55000J)\\E=27500J

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You need to know the height of a tower, but darkness obscures the ceiling. You note that a pendulum extending from the ceiling a
Sonja [21]

Answer:

L=55.9m

Explanation:

The equation for the period of a simple pendulum is:

T=2\pi\sqrt{\frac{L}{g}}

In our case what we know is the period and the acceleration of gravity, and we need to know the length of the pendulum, so we can write:

L=(\frac{T}{2\pi})^2g

Which for our values is:

L=(\frac{15s}{2\pi})^2(9.81m/s^2)=55.9m

6 0
3 years ago
9. A radioisotope has a half-life of 4.50 min and an initial decay rate of 8400 Bq. What will be
Akimi4 [234]

Answer:

525 Bq

Explanation:

The decay rate is directly proportional to the amount of radioisotope, so we can use the half-life equation:

A = A₀ (½)^(t / T)

A is the final amount

A₀ is the initial amount,

t is the time,

T is the half life

A = (8400 Bq) (½)^(18.0 min / 4.50 min)

A = (8400 Bq) (½)^4

A = (8400 Bq) (1/16)

A = 525 Bq

8 0
3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia
Eduardwww [97]

Answer:

From the data we know that runner A and runner B are 11 km apart from the start because (6+5) km

So the runner from the east direction has distance as unknown km, rate= 9 k/h ; time= d/r=x/9 hr

So runner towards the west will be

distance = 11-x, rate= 8 k/h, time = d/r = (11-x)/8

So equating east and west time we have

x/9= (11-x)/8

8x=99-9x

17x=99

x=5.92 km

That is the distance covered by runner towards the east and he will meet the runner toward the west at

6-5.92=0.08 km west of the flagpole.

7 0
3 years ago
Which statement explains whether or not a person should use an experiment of a ball rolling down a hill as evidence that the for
Ksenya-84 [330]

The ball raised up the hill is given gravitational potential energy, which

causes it to roll spontaneously down the hill.

The statement that explains whether the ball rolling down the hill

experiment should be used is; <u>The experiment shows the ball falls toward </u>

<u>the bottom of the hill, so it provides direct evidence that gravity pulls an </u>

<u>object downward. They should use it.</u>

Reason:

The equation for the velocity of a ball falling down a hill is v = \sqrt{\dfrac{10}{7} \cdot g \cdot h}

Therefore, by increasing the height from which the ball rolls down the hill,

the velocity of the ball increases, which indicates that the ball is

accelerating, and therefore, being acted on by a force, the force of gravity.

Therefore;

Given that the ball falls or moves with increasing speed towards

the bottom of the hill, which shows that the motion is due to Earth's pull

known as the gravitational force, the experiment should be used.

Learn more here:

brainly.com/question/3175380

8 0
2 years ago
Please help :( A ray of laser light strikes a glass surface at an angle θa = 22.5° to the normal. What is the angle θb of the re
pshichka [43]

Answer:

Explanation:

We shall apply law of refraction which is as follows

sin i / sinr = μ  , where i is angle of incidence , r is angle of refraction and μ is refractive index

here i = θa = 22.5°

r = θb

μ  = 1.77

sin22.5 / sinθb = 1.77

.3826 / sinθb = 1.77

sinθb = .216

θb  = 12.5 °.

4 0
3 years ago
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