Answer:
£14889.30
Step-by-step explanation:
The cost of the car = £15500.
For the first year,
depreciation = £15500 x 1%
= £155
Its worth after the first year = £15500 - £155
= £15345
For the 2nd year,
depreciation = £15345 x 1%
= £153.45
Its worth after the second year = £15345 - £153.45
= £15191.55
For the 3rd year,
depreciation = £15191.55 x 1%
= £151.9155
Its worth after the third year = £15191.55 - £151.9155
= £15039.6345
For the 4th year,
depreciation = £15039.6345 x 1%
= £150.3963
Its worth after the fourth year = £15039.6345 - £150.3963
= £14889.2382
Thus, the worth of the car in 4 years would be £14889.30
Answer:
18 x 15 x 3 is 810. The volume is 810.
Step-by-step explanation:
Volume of cuboid= Length*Width*Breadth
Volume of container= 18 cm X 15 cm X 3cm
Volume of container=810
Hope i helped
Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
Correlation Coefficient (r) = 0.989
alph=0.05
Number of observations (n) = 8
determine if there is a linear correlation between chest size and weight.
Yes, there exists a linear relationship between chest size and weight as the value of the correlation Coefficient exceeds the critical value.
What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?
To determine the the proportion of variation in weight that can be explained by the linear regression line between weight and chest size, we need to obtain the Coefficient of determination(r^2) of the model.
r^2 = square of the correlation Coefficient
r^2 = 0.989^2 = 0.978121
Hence, about 0.978 (97.8%) of the variation in weight can be explained by the linear relationship between weight and chest size.
Answer: D
Step-by-step explanation:
because its right
Answer:
y = 1/4x + 3
Step-by-step explanation:
m = 1/4, (-4,2)
y -2 = 1/4(x - - 4)
y - 2 = 1/4 (x + 4)
y - 2 = 1/4x + 1
y = 1/4x + 1 + 2
y = 1/4x + 3
