Answer:
Present Time
Let X= Eric's age (4/5)X= Seth's age
Question: What are their ages now?________________________________________________________________________
Past (21 years ago)
X-21 =Eric's age (4/5)X-21=Seth's age
2*[4/5(X-21]=Eric's age
Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution
_______________________________________________________________________
X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.
X-21+42=(8/5) X
X+21 = (8/5)X Subtract "X" from both sides.
21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3
21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.
Then find 4/5 (X)= Seth's age
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Answer:
6
Step-by-step explanation:
Mr. Kramer has pencils for his class = 30
Students in his class = 22
Pencils he would like to give each student = 2
How many more pencils does Mr. Kramer need to buy so that each student will receive 2 pencils = ?
Total pencils Mr. Kramer need to buy so that each student will receive 2 pencils = 22 × 2
= 44
= 44 - 30
= 6
Mr. Kramer need to buy 6 more pencils so that each student will receive 2 pencils
Answer:
(a) 0.05 minutes per calorie burned
(b) Slope = 20
Step-by-step explanation:
(a) If 200 calories are burned in 10 minutes...then what about 1 calorie
; 1/200 × 10 = 0.05 minutes
(b) Slope of the graph...;just take any two points on the graph...which are (10;200) and (20;400)
Slope = (400 - 200) ÷ (20 - 10)
;Slope = 200 ÷ 10
;Slope = 20
Answer:
A. 12 miles
B. 9 miles
C. 2 hours
D. 5 hours
E. Max did not move
F. 9 hours
G. 5 hours
hope this helps :)
Step-by-step explanation:
