Question

A point charge that is exactly q =3 mu or micro CC is at the origin. In this problem, assume that the Coulomb constant k = 8.99 times 109 N m2/C2 exactly.(a) Find the potential V on the x axis at x = 3.00 m and at x = 3.01 m. In this part, enter your answers to exactly 6 signfificant figures.

Answer 1

Answer:

(a) V1 = 8990.00 V

V2 = 8960.13 V

Explanation:

Parameters given:

q =3 mC

k = 8.99 * 10⁹ Nm²/C²

x1 = 3 m

x2 = 3.01 m

Electric potential is given as:

V = kq/r

Where

k = Coulombs constant

q = charge

r = distance

Potential at x1 is:

V1 = (8.99 * 10⁹ * 0.000003)/(3)

V1 = 8990.00V

Potential at x2 is:

V2 = (8.99 * 10⁹ * 0.003)/(3.01)

V2 = 8960.13 V

Answer 2

Answer:

a) 8,990.00 V   b) 8,960.13 V

Explanation:

a) The potential due to a point charge, can be found from the expression of  Coulomb's Law, as follows:

$V = \frac{k*q}{r}$

where k = 8.99*10⁹ N*m²/C², q = 3.00*10⁻⁶ C, and r = 3.00 m.

Replacing by this values, we can find the potential V as follows:

$V = \frac{8.99e9 N*m2/C2*3.00e-6C}{3.00m} = 8,990.00 V$

b) Repeating the process for r = 3.01m:

$V = \frac{8.99e9 N*m2/C2*3.00e-6C}{3.01m} = 8,960.13 V$