By bring their legs close to their bodies, they are decreasing the length of the pendulum which help them move more quickly.
A pendulum is nothing but a body suspended from a fixed point so that it can swing back and forth under the influence of gravity.
Here in this case Gibbons are bringing their legs close to their bodies and reducing the length of the pendulum. Since as the length of the pendulum increases the speed of the movement will be reduced. By bringing their legs close to their bodies they are reducing the length and in turn their speed increase and they move quickly.
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Answer:
28.8 meters
Explanation:
We must first determine at which velocity the ball hits the water. To do so we will:
1) Assume no air resistance.
2) Use the Law of conservation of mechanical energy: E=K+P
Where
E is the mechanical energy (which is constant)
K is the kinetic energy.
P is the potential energy.
With this we have
Where:
m is the balls's mass <- we will see that it cancels out and as such we don't need to know it.
v is the speed when it hits the water.
g is the gravitational constant (we will assume g=9.8
.
h is the height from which the ball fell.
Because when we initially drop the ball, all its energy is potential (and
) and when it hits the water, all its energy is kinetic (
. And all that potential was converted to kinetic energy.
Now, from
we can deduce that 
Therefore v=9.6
Now, to answer how deep is the lake we just need to multiply that speed by the time it took the ball to reach the bottom.
So D=9.6
*3
=28.8
Which is our answer.
Answer:
Explanation:Here's li
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bit.
Answer:
(a) the compression of the spring when the block comes to rest is 4cm
(b) speed of the block is 0.427 m/s
Explanation:
Given;
mass of the block, m = 1.6 kg
spring constant, k = 902 N/m
initial speed of the block, v₀ = 0.95 m/s
(a) the compression of the spring when the block comes to rest
when the block comes to rest, the final speed, vf = 0
Apply the law of conservation of energy;
¹/₂kx² = ¹/₂mv₀²
kx² = mv₀²

x = 4 cm
(b) speed of the block
Apply the law of conservation of energy;
¹/₂mv² = ¹/₂kx²
mv² = kx²
