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3 years ago

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What is a Super Massive Black Hole?

1 answer:

Serggg [28]3 years ago

4 0

Answer:

I dont really know much but i know that it swallow anything it comes across in space.

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Explain why distance has a larger impact on the gravitational force between two objects than mass does.

yKpoI14uk [10]

if the mass of both of the objects is doubled, then the force of gravity between them is quadrupled. Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.

8 0

2 years ago

A wire 3.22 m long and 7.32 mm in diameter has a resistance of 11.9 mΩ. A potential difference of 33.7 V is applied between the

Scorpion4ik [409]

Answer:

(a) Current is 2831.93 A

(b) $8.40A/m^2$

(c) $\rho =15.52\times 10^{-9}ohm-m$

Explanation:

Length of wire l = 3.22 m

Diameter of wire d = 7.32 mm = 0.00732 m

Cross sectional area of wire

$A=\pi r^2=3.14\times 0.00366^2=4.20\times 10^{-5}m^2$

Resistance $R=11.9mohm=11.9\times 10^{-3}ohm$

Potential difference V = 33.7 volt

(A) current is equal to

$i=\frac{V}{R}=\frac{33.7}{11.9\times 10^{-3}}=2831.93A$

(B) Current density is equal to

$J=\frac{i}{A}$

$J=\frac{2831.93}{4.20\times 10^{-5}}=8.40A/m^2$

(c) Resistance is equal to

$R=\frac{\rho l}{A}$

$11.9\times 10^{-3}=\frac{\rho \times 3.22}{4.20\times 10^{-5}}$

$\rho =15.52\times 10^{-9}ohm-m$

4 0

3 years ago

The barcoding process is helpful because it A. increases the security and accuracy of stored and dispensed medications. B. helps

Dvinal [7]

A. increases with security and accuracy of stored and dispense medications

4 0

3 years ago

Read 2 more answers

Help please an observer at the North Pole sees the moon phase shown below. What Moon phase will be observed approximately one we

ziro4ka [17]

Answer:

it should be a new moon

Explanation:

4 0

3 years ago

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi

maria [59]

Answer:

a) a = 5.03x10¹³ m/s²

b) $V_{f} = 4.4 \cdot 10^{5} m/s$

Explanation:

a) The acceleration of the positron can be found as follows:

$F = q*E$ (1)

Also,

$F = ma$ (2)

By entering equation (1) into (2), we have:

$a = \frac{F}{m} = \frac{qE}{m}$

<u>Where:</u>

F: is the electric force

m: is the particle's mass = 9.1x10⁻³¹ kg

q: is the charge of the positron = 1.6x10⁻¹⁹ C

E: is the electric field = 286 N/C

$a = \frac{qE}{m} = \frac{1.6 \cdot 10^{-19} C*286 N/C}{9.1 \cdot 10^{-31} kg} = 5.03 \cdot 10^{13} m/s^{2}$

b) The positron's speed can be calculated using the following equation:

$V_{f} = V_{0} + at$

<u>Where</u>:

$V_{f}$ : is the final speed =?

$V_{0}$ : is the initial speed =0

t: is the time = 8.70x10⁻⁹ s

$V_{f} = V_{0} + at = 0 + 5.03 \cdot 10^{13} m/s^{2}*8.70 \cdot 10^{-9} s = 4.4 \cdot 10^{5} m/s$

I hope it helps you!

4 0

3 years ago