Answer:
1. The current will drop to half of its original value.
Explanation:
The problem can be solved by using Ohm's law:

where
V is the voltage across the circuit
R is the resistance of the circuit
I is the current
We can rewrite it as

In this problem, we have:
- the resistance of the circuit remains the same: R' = R
- the voltage is decreased to half of its original value: 
So, the new current will be

so, the current will drop to half of its original value.
The velocity at the maximum height will always be 0. Therefore, you will count your final velocity as 0, and your initial velocity as 35 m/s. Next, we know that the acceleration will be 9.8 m/s^2. How? Because the ball is thrown directly upward, and the only force acting on it will be the force of gravity pushing it back down.
The formula we use is h = (Vf^2 - Vi^2) / (2*-9.8m/s^2)
Plugging everything in, we have h = (0-1225)/(19.6) = 62.5 meters is the maximum height.
Answer:
(a) x0 = 0m and y0 = 49.0m
(b) Vox = 15.0m/s Voy = 0m/s
(c) Vx = Vo = 15.0m/s and Vy = -gt
(d) X = 15.0t and y = 49.0 - 4.9t²
(e) t = 3.16s
(f) Vf = 34.4m/s
Explanation:
Answer is c that is he particles move perpendicular to the direction of the wave.