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amid [387]
3 years ago
5

A boy leaps over a rock.

Physics
1 answer:
n200080 [17]3 years ago
5 0

Answer:

When the boy has first started the motion this is similar to what kangaroo moves.

Initially the  boy was standing and only force of gravity due to his own mass was acting.

When the boy started leaping an acceleration happened that caused his motion. His leg were bent to push above ground to leap, this provided an acceleration to the center of mass of the boy. and equal and opposite force was acted on the boys feet's touching the ground.  

So according to Newton's  third law action force was acted on the ground by the boy feet, and the reaction force was the opposite force by the rock and this caused the boy to accelerate.

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6 0
2 years ago
Mary and her younger brother Alex decide to ride the carousel at the State Fair. Mary sits on one of the horses in the outer sec
Alex

Answer:

ωM = 1.7 rad/s

vM = 3.4 m/s

ωA = 1.7 rad/s

vA =  1.7  m/s

Explanation:

Calculation of the angular speed (ω)

We use the following formula for circular motion:

ω = θ / t Formula (1)

Where:

ω: angular speed (rad/s)

θ:angle that the particle travels (rad)

t: time interval (s)

Equivalence

1 revolution = 2π rad

Data

θ= 1 revolution = 2π rad

t = 3.7 s

We replace data in the formula (1):

ω = (2π rad) / (3.7s )= 1.7 rad/s

Because the angular speed depends only on the number of turns in a time interval then Mary's angular speed (ωM) is equal to Alex's angular speed (ωA).

ωM = ωA = 1.7 rad/s

Calculation of the  tangential speed (v)

We use the following formula for circular motion:

v = ω*r  Formula (2)

Where:

v : tangential speed (m/s)

ω: angular speed ( rad/s)

r  : radius of the circular path (m)

Data

ωM = ωM = ω= 1.7 rad/s

rM = 2m  : Mary's circular path radius

rA = 1m :  Alex's circular path radius

We apply the formula (2) to calculate v:

vM = ω* rM = (1.7) (2) = 3.4 m/s

vA = ω* rA = (1.7) (1) =  1.7  m/s

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